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+-> lambda expressions without specifying typesIf I did not make a mistake, the grammar in the Aldor User Guide seems
to allow something like x+->x+1. But in the program below the Aldor compiler (1.1.0) cannot/does not infer the type of the lambda expression in baz. Stephen, is that intended or is that just a short-coming of the compiler? Ralf --------------------------------------------------------- >aldor -fx -laldor aaa.as "aaa.as", line 9: baz(i: Integer): Integer == foo((x +-> x-1), i); ...................................^ [L9 C36] #1 (Error) Expecting a comma separated list of parameters. ---rhxBEGIN aaa.as #include "aldor" Aaa: with { foo: (Integer -> Integer, Integer) -> Integer; bar: Integer -> Integer; bar: Integer -> Integer; } == add { foo(f: Integer->Integer, i: Integer): Integer == f i; bar(i: Integer): Integer == foo((x: Integer): Integer +-> x+1, i); baz(i: Integer): Integer == foo((x +-> x-1), i); } main(): () == { import from String, Character, TextWriter, Integer, Aaa; stdout << foo(bar, 1) << newline; stdout << bar 1 << newline; stdout << bar 1 << newline; } main(); ---rhxEND aaa.as _______________________________________________ Aldor-l mailing list Aldor-l@... http://aldor.org/mailman/listinfo/aldor-l_aldor.org |
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