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[AMPL 2576] Assignment and constraintsHi all, I have the following. I'm keeping the syntax simple here for ease of discussion. var L{0..4}, M{0..4}; var final >= 0; c1{j in 0..4}: L[j] <= M[j]; c2{j in 1..4}: L[j] = L[0]; c{j in 0..4}: final = sum{j} (M[j] - L[j]); minimize{j in 0..4}: final; #need this explicitly? #c3{j in 0..4}: L[0] <= M[j]; This crashes FilMINT solver. Unfortunately, I don't get any indication of what or where the problem is when the solver crashes.. So, I tried it with MINOS solver; it ignores integrality (not related to the variables shown here) but solves the problem. However, it picks L[0] to have a value that is not <= each M[j] which makes final negative. But this is not what I expected. So, my question is this - when L[1..4] is assigned L[0], will L[0] value be selected by the solver to be <= each of the M[j] per constraint c1? [Or, does the solver pick L[0] <= M[0], assign L[0] to the rest of the L[j] and then crash if c1 or final_LB is violated? In that case, I'd have to include c3 constraint but even that hasn't helped me with FilMINT so far. However, me forcing L[0] to have a valid value (through a constraint) helps..] Sincere thanks in advance for any and all information! --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "AMPL Modeling Language" group. To post to this group, send email to ampl@... To unsubscribe from this group, send email to ampl+unsubscribe@... For more options, visit this group at http://groups.google.com/group/ampl?hl=en -~----------~----~----~----~------~----~------~--~--- |
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[AMPL 2577] Re: Assignment and constraints> minimize{j in 0..4}: final; With this declaration you have 5 objective functions. Which one are you minimizing? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "AMPL Modeling Language" group. To post to this group, send email to ampl@... To unsubscribe from this group, send email to ampl+unsubscribe@... For more options, visit this group at http://groups.google.com/group/ampl?hl=en -~----------~----~----~----~------~----~------~--~--- |
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[AMPL 2583] Re: Assignment and constraintsWhen you write "c1{j in 0..4}: L[j] <= M[j]" AMPL sets j successively to the values 0, 1, 2, 3, 4 and generates the corresponding constraints L[0] <= M[0], L[1] <= M[1], L[2] <= M[2], L[3] <= M[3], L[4] <= M[4]. Evidently you're looking for something else, so you need to write your constraint differently. The constraint "c3{j in 0..4}: L[0] <= M[j]" seems more nearly like what you are describing, since it generates L[0] <= M[0], L[0] <= M[1], L[0] <= M[2], ... To be sure you could get a listing of all the constraints generated by giving the AMPL commands "expand c1;", "expand c3;" and the like. The solver does not have any effect on what constraints AMPL generates; only after AMPL generates all the constraints (and the objective) does the solver try to find a solution for them. If FilMINT is crashing on some problem then you best bet is to bring that to the attention of FilMINT's developers. Bob Fourer 4er@... > -----Original Message----- > From: ampl@... [mailto:ampl@...] On Behalf Of x > Sent: Thursday, June 04, 2009 1:16 PM > To: ampl@... > Subject: [AMPL 2576] Assignment and constraints > > > > Hi all, > > I have the following. I'm keeping the syntax simple here for ease of > discussion. > > var L{0..4}, M{0..4}; > var final >= 0; > > c1{j in 0..4}: L[j] <= M[j]; > > c2{j in 1..4}: L[j] = L[0]; > > c{j in 0..4}: final = sum{j} (M[j] - L[j]); > > minimize{j in 0..4}: final; > > #need this explicitly? > #c3{j in 0..4}: L[0] <= M[j]; > > This crashes FilMINT solver. Unfortunately, I don't get any indication of > what or where the problem is when the solver crashes.. So, I tried it with > MINOS solver; it ignores integrality (not related to the variables shown > here) but solves the problem. However, it picks L[0] to have a value that > is not <= each M[j] which makes final negative. But this is not what I > expected. > > So, my question is this - when L[1..4] is assigned L[0], will L[0] value > be selected by the solver to be <= each of the M[j] per constraint c1? > > [Or, does the solver pick L[0] <= M[0], assign L[0] to the rest of the > L[j] and then crash if c1 or final_LB is violated? In that case, I'd have > to include c3 constraint but even that hasn't helped me with FilMINT so > far. However, me forcing L[0] to have a valid value (through a constraint) > helps..] > > Sincere thanks in advance for any and all information! > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "AMPL Modeling Language" group. To post to this group, send email to ampl@... To unsubscribe from this group, send email to ampl+unsubscribe@... For more options, visit this group at http://groups.google.com/group/ampl?hl=en -~----------~----~----~----~------~----~------~--~--- |
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