这个问题去年有人讨论过，我也是搜索去年的邮件搜出来的相关信息。
我安装的是python2.5，在 urllib2.py 文件的第 1068 行。
也就是 AbstractHTTPHandler 这个类的 do_open 方法中。
注释说，addinfourl 类对持久链接没准备好。。。
代码片段如下：
# We want to make an HTTP/1.1 request, but the
addinfourl
# class isn't prepared to deal with a persistent connection.
# It will try to read all remaining data from the socket,
# which will block while the server waits for the next request.
# So make sure the connection gets closed after the (only)
# request.
headers["Connection"] = "close"
headers = dict(
(name.title(), val) for name, val in headers.items())
try:
h.request(req.get_method(), req.get_selector(), req.data, headers)
r = h.getresponse()
except socket.error, err: # XXX what error?
raise URLError(err)
|
fluke.l 写道:
urllib2
中是什么地方的硬编码导致和keep-alive不兼容?
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