C program help

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C program help

by spiros85 :: Rate this Message:

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Hi guys of dear forum!I am a new programmer in C programming language and i have a question for you about the following C code:
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int x;
    int answer;
    int right;
    int wrong;
    printf("This is a program of sum\n");
    right = 0; /*Initialization of right value*/
    wrong = 0; /*Initialization of wrong value*/
    for(x = 1; x <= 10; x++)[QUOTE][/QUOTE]
    {
          printf("What is %d + %d: ", x, x);
          scanf("%d", &answer);
          printf("The sum is %d\n", answer);
          printf("\a");
          if(answer == x + x)
          {
             printf("%d is RIGHT answer\n", answer);
             right++; /*Saves and increases the amount of right answers*/
          }
          else
          {
             printf("%d is WRONG answer\n", answer);
             b[10] = answer;
             wrong++; /*Saves and increases the amount of wrong answers*/
             printf("The correct answer is %d\n", x + x);
          }
    }
    printf("The right answers are %d and the wrong are %d\n", right, wrong);
    fflush(stdin);
    getchar();
}
 
First, I use DEV C++ compiler!This program asks from user to find the sum of 1+1,2+2 until for loop reaches 10.As you can observe with right++ and wrong++ i can define and print to the screen the amount of right or wrong numbers!
My question is how could I define the number of correct and wrong numbers in collaboration with their amount?For example:
The right answers are 8 and wrong are 2
The right answers are 2 4 6 8 10 12 14 16
The wrong answers are 22 44

Re: C program help

by shiva kumar :: Rate this Message:

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here is solution
 
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int x;
    int answer;
    int right;
    int wrong;
    int righta[100];
    int wronga[100];
    int i;

    printf("This is a program of sum\n");
    right = 0; /*Initialization of right value*/
    wrong = 0; /*Initialization of wrong value*/
    for(x = 1; x <= 10; x++)
    {
          printf("What is %d + %d: ", x, x);
          scanf("%d", &answer);
          printf("The sum is %d\n", answer);
          printf("\a");
          if(answer == x + x)
          {
             printf("%d is RIGHT answer\n", answer);
             righta[right]=answer;
             right++; /*Saves and increases the amount of right answers*/
          }
          else
          {
             printf("%d is WRONG answer\n", answer);
             wronga[wrong] = answer;
             wrong++; /*Saves and increases th      }
    }
    righta[right]=0;
    wronga[wrong]=0;
    printf("The right answers are %d and the wrong are %d\n", right, wrong);
    printf("The right answers are ");
    for(i=0;righta[i];i++){
        printf("%d\t",righta[i]);
    }
    printf("\nThe wrong answers are ");
    for(i=0;wronga[i];i++){
        printf("%d\t",wronga[i]);
    }
    fflush(stdin);
    getchar();
}



e amount of wrong answers*/
             printf("The correct answer is %d\n", x + x);
                                                                                             




spiros85 wrote:
Hi guys of dear forum!I am a new programmer in C programming language and i have a question for you about the following C code:
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int x;
    int answer;
    int right;
    int wrong;
    printf("This is a program of sum\n");
    right = 0; /*Initialization of right value*/
    wrong = 0; /*Initialization of wrong value*/
    for(x = 1; x <= 10; x++)[QUOTE][/QUOTE]
    {
          printf("What is %d + %d: ", x, x);
          scanf("%d", &answer);
          printf("The sum is %d\n", answer);
          printf("\a");
          if(answer == x + x)
          {
             printf("%d is RIGHT answer\n", answer);
             right++; /*Saves and increases the amount of right answers*/
          }
          else
          {
             printf("%d is WRONG answer\n", answer);
             b[10] = answer;
             wrong++; /*Saves and increases the amount of wrong answers*/
             printf("The correct answer is %d\n", x + x);
          }
    }
    printf("The right answers are %d and the wrong are %d\n", right, wrong);
    fflush(stdin);
    getchar();
}
 
First, I use DEV C++ compiler!This program asks from user to find the sum of 1+1,2+2 until for loop reaches 10.As you can observe with right++ and wrong++ i can define and print to the screen the amount of right or wrong numbers!
My question is how could I define the number of correct and wrong numbers in collaboration with their amount?For example:
The right answers are 8 and wrong are 2
The right answers are 2 4 6 8 10 12 14 16
The wrong answers are 22 44