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Call to object function, want to PHP interpret returned string

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	Call to object function, want to PHP interpret returned string by John Allsopp :: Rate this Message: Reply to Author \| View Threaded \| Show Only this Message Hi At the top of a webpage I have: <?php include_once("furniture.php"); $myFurniture = new furniture(); echo $myFurniture->getTop("my company title"); ?> to deliver the first lines of HTML, everything in HEAD and the first bits of page furniture (menu, etc). In the furniture object in getTop(), I want to return a string that includes the CSS file that I call with an include_once. But the include_once isn't interpreted by PHP, it's just outputted. So from: $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 Transitional//EN' ........ <?php include_once('styles3.txt'); ?> ......."; return $toReturn; I get <?php include_once('styles3.txt'); ?> in my code. Do I really have to break up my echo $myFurniture->getTop("my company title"); call to getTopTop, then include my CSS, then call getTopBottom, or can I get PHP to interpret that text that came back? PS. I may be stupid, this may be obvious .. I don't program PHP every day Thanks in advance for your help :-) Cheers J -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
	Re: Call to object function, want to PHP interpret returned string by David Robley-2 :: Rate this Message: Reply to Author \| View Threaded \| Show Only this Message John Allsopp wrote: > Hi > > At the top of a webpage I have: > > <?php > include_once("furniture.php"); > $myFurniture = new furniture(); > echo $myFurniture->getTop("my company title"); > ?> > > to deliver the first lines of HTML, everything in HEAD and the first > bits of page furniture (menu, etc). > > In the furniture object in getTop(), I want to return a string that > includes the CSS file that I call with an include_once. But the > include_once isn't interpreted by PHP, it's just outputted. So from: > > $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 > Transitional//EN' ........ > <?php > include_once('styles3.txt'); > ?> > ......."; > > return $toReturn; > > I get > > <?php > include_once('styles3.txt'); > ?> > > in my code. > > Do I really have to break up my echo $myFurniture->getTop("my company > title"); call to getTopTop, then include my CSS, then call getTopBottom, > or can I get PHP to interpret that text that came back? > > PS. I may be stupid, this may be obvious .. I don't program PHP every day > > Thanks in advance for your help :-) > > Cheers > J First guess is that your page doing the including doesn't have a filename with a .php extension, and your server is set to only parse php in files with a .php extension. Cheers -- David Robley If you saw a heat wave, would you wave back? Today is Boomtime, the 41st day of Confusion in the YOLD 3175. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
	Re: Re: Call to object function, want to PHP interpret returned string by John Allsopp :: Rate this Message: Reply to Author \| View Threaded \| Show Only this Message David Robley wrote: > John Allsopp wrote: > > >> Hi >> >> At the top of a webpage I have: >> >> <?php >> include_once("furniture.php"); >> $myFurniture = new furniture(); >> echo $myFurniture->getTop("my company title"); >> ?> >> >> to deliver the first lines of HTML, everything in HEAD and the first >> bits of page furniture (menu, etc). >> >> In the furniture object in getTop(), I want to return a string that >> includes the CSS file that I call with an include_once. But the >> include_once isn't interpreted by PHP, it's just outputted. So from: >> >> $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 >> Transitional//EN' ........ >> <?php >> include_once('styles3.txt'); >> ?> >> ......."; >> >> return $toReturn; >> >> I get >> >> <?php >> include_once('styles3.txt'); >> ?> >> >> in my code. >> >> Do I really have to break up my echo $myFurniture->getTop("my company >> title"); call to getTopTop, then include my CSS, then call getTopBottom, >> or can I get PHP to interpret that text that came back? >> >> PS. I may be stupid, this may be obvious .. I don't program PHP every day >> >> Thanks in advance for your help :-) >> >> Cheers >> J >> > > First guess is that your page doing the including doesn't have a filename > with a .php extension, and your server is set to only parse php in files > with a .php extension. > > > > Cheers > Ah, thanks. It's a PHP object returning a string, I guess the PHP interpreter won't see that. So, maybe my object has to write a file that my calling file then includes after the object function call. Doesn't sound too elegant, but is that how it's gotta be? Cheers J -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
	Re: Re: Call to object function, want to PHP interpret returned string by Stuart-47 :: Rate this Message: Reply to Author \| View Threaded \| Show Only this Message 2009/7/6 John Allsopp <john@...>: > David Robley wrote: >> >> John Allsopp wrote: >> >> >>> >>> Hi >>> >>> At the top of a webpage I have: >>> >>> <?php >>> include_once("furniture.php"); >>> $myFurniture = new furniture(); >>> echo $myFurniture->getTop("my company title"); >>> ?> >>> >>> to deliver the first lines of HTML, everything in HEAD and the first >>> bits of page furniture (menu, etc). >>> >>> In the furniture object in getTop(), I want to return a string that >>> includes the CSS file that I call with an include_once. But the >>> include_once isn't interpreted by PHP, it's just outputted. So from: >>> >>> $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 >>> Transitional//EN' ........ >>> <?php >>> include_once('styles3.txt'); >>> ?> >>> ......."; >>> >>> return $toReturn; >>> >>> I get >>> >>> <?php >>> include_once('styles3.txt'); >>> ?> >>> >>> in my code. >>> >>> Do I really have to break up my echo $myFurniture->getTop("my company >>> title"); call to getTopTop, then include my CSS, then call getTopBottom, >>> or can I get PHP to interpret that text that came back? >>> >>> PS. I may be stupid, this may be obvious .. I don't program PHP every day >>> >>> Thanks in advance for your help :-) >>> >>> Cheers >>> J >>> >> >> First guess is that your page doing the including doesn't have a filename >> with a .php extension, and your server is set to only parse php in files >> with a .php extension. >> >> >> >> Cheers >> > > Ah, thanks. It's a PHP object returning a string, I guess the PHP > interpreter won't see that. > > So, maybe my object has to write a file that my calling file then includes > after the object function call. Doesn't sound too elegant, but is that how > it's gotta be? You appear to be looking for the eval function: http://php.net/eval However, in 99.99% of cases using eval is not the right solution. In your case there are two ways to solve it. The first way, assuming the thing you're trying to include is a stylesheet, is to use an external link to a CSS file. That would be the "normal" way to include a stylesheet in an HTML page and is far more efficient that including it inline. If it's not just a stylesheet that you're including then you'll want to load the file in the getTop method. For example... $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 Transitional//EN' ........"; $toReturn.= file_get_contents('styles3.txt'); $toReturn.= '..........'; Simple as that. -Stuart -- http://stut.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
	Re: Re: Call to object function, want to PHP interpret returned string by David Robley-2 :: Rate this Message: Reply to Author \| View Threaded \| Show Only this Message John Allsopp wrote: > David Robley wrote: >> John Allsopp wrote: >> >> >>> Hi >>> >>> At the top of a webpage I have: >>> >>> <?php >>> include_once("furniture.php"); >>> $myFurniture = new furniture(); >>> echo $myFurniture->getTop("my company title"); >>> ?> >>> >>> to deliver the first lines of HTML, everything in HEAD and the first >>> bits of page furniture (menu, etc). >>> >>> In the furniture object in getTop(), I want to return a string that >>> includes the CSS file that I call with an include_once. But the >>> include_once isn't interpreted by PHP, it's just outputted. So from: >>> >>> $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 >>> Transitional//EN' ........ >>> <?php >>> include_once('styles3.txt'); >>> ?> >>> ......."; >>> >>> return $toReturn; >>> >>> I get >>> >>> <?php >>> include_once('styles3.txt'); >>> ?> >>> >>> in my code. >>> >>> Do I really have to break up my echo $myFurniture->getTop("my company >>> title"); call to getTopTop, then include my CSS, then call getTopBottom, >>> or can I get PHP to interpret that text that came back? >>> >>> PS. I may be stupid, this may be obvious .. I don't program PHP every >>> day >>> >>> Thanks in advance for your help :-) >>> >>> Cheers >>> J >>> >> >> First guess is that your page doing the including doesn't have a filename >> with a .php extension, and your server is set to only parse php in files >> with a .php extension. >> >> >> >> Cheers >> > Ah, thanks. It's a PHP object returning a string, I guess the PHP > interpreter won't see that. > > So, maybe my object has to write a file that my calling file then > includes after the object function call. Doesn't sound too elegant, but > is that how it's gotta be? > > Cheers > J I think I misunderstood your explanation :-) Can you show the actual content of furniture.php? I wonder if there are missing <?php ?> tags?? Cheers -- David Robley And it's only ones and zeros. Today is Boomtime, the 41st day of Confusion in the YOLD 3175. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
	Re: Re: Call to object function, want to PHP interpret returned string by John Allsopp :: Rate this Message: Reply to Author \| View Threaded \| Show Only this Message Stuart wrote: > 2009/7/6 John Allsopp <john@...>: > >> David Robley wrote: >> >>> John Allsopp wrote: >>> >>> >>> >>>> Hi >>>> >>>> At the top of a webpage I have: >>>> >>>> <?php >>>> include_once("furniture.php"); >>>> $myFurniture = new furniture(); >>>> echo $myFurniture->getTop("my company title"); >>>> ?> >>>> >>>> to deliver the first lines of HTML, everything in HEAD and the first >>>> bits of page furniture (menu, etc). >>>> >>>> In the furniture object in getTop(), I want to return a string that >>>> includes the CSS file that I call with an include_once. But the >>>> include_once isn't interpreted by PHP, it's just outputted. So from: >>>> >>>> $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 >>>> Transitional//EN' ........ >>>> <?php >>>> include_once('styles3.txt'); >>>> ?> >>>> ......."; >>>> >>>> return $toReturn; >>>> >>>> I get >>>> >>>> <?php >>>> include_once('styles3.txt'); >>>> ?> >>>> >>>> in my code. >>>> >>>> Do I really have to break up my echo $myFurniture->getTop("my company >>>> title"); call to getTopTop, then include my CSS, then call getTopBottom, >>>> or can I get PHP to interpret that text that came back? >>>> >>>> PS. I may be stupid, this may be obvious .. I don't program PHP every day >>>> >>>> Thanks in advance for your help :-) >>>> >>>> Cheers >>>> J >>>> >>>> >>> First guess is that your page doing the including doesn't have a filename >>> with a .php extension, and your server is set to only parse php in files >>> with a .php extension. >>> >>> >>> >>> Cheers >>> >>> >> Ah, thanks. It's a PHP object returning a string, I guess the PHP >> interpreter won't see that. >> >> So, maybe my object has to write a file that my calling file then includes >> after the object function call. Doesn't sound too elegant, but is that how >> it's gotta be? >> > > You appear to be looking for the eval function: http://php.net/eval > > However, in 99.99% of cases using eval is not the right solution. In > your case there are two ways to solve it. > > The first way, assuming the thing you're trying to include is a > stylesheet, is to use an external link to a CSS file. That would be > the "normal" way to include a stylesheet in an HTML page and is far > more efficient that including it inline. > > If it's not just a stylesheet that you're including then you'll want > to load the file in the getTop method. For example... > > $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 > Transitional//EN' ........"; > $toReturn.= file_get_contents('styles3.txt'); > $toReturn.= '..........'; > > Simple as that. > > -Stuart > > Thanks guys. Yes, actually file_get_contents didn't work for me, and yes you're right, of course I should be including my CSS like <LINK rel='stylesheet' type='text/css' media='screen' href='style3.css' title='style1'> in the header. The style3.txt file I was trying to PHP include was there so I could include more than one stylesheet and make just one amendment. One for printing and I'm guessing one for mobile. All that file contained was the <LINK... line above. That was legacy code. Now I have a furniture object, of course, I can put my stylesheet code in one place there just as part of the header, and have no need for style3.txt. Thanks for all your help. J -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php