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Problem with jasypt and linux

by ilyes :: Rate this Message:

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i have a problem when i run my application inside lunix but it work so well inside windows envirnoment

when i run my application inside linux it show me that i cant find the envrinoment variable that i use to crypte my password but when i make echo $myVariable it show me the correct value..

Does someone can help me!!! sorry for my bad english :)

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