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Questions about wsrf exampleHi,
In wsrf example, it seems that WSResource instances are assembled into ServiceGroup automatically. Can anyone tell me how this is done and which java class is reponsible for this? Thanks. SARA |
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Re: Questions about wsrf exampleHiya,
http://ws.apache.org/muse/docs/2.2.0/manual/how-to/wsrf-add-service-groups.html and in combination with advertisements: http://www.ibm.com/developerworks/library/ac-museadv/index.html cheers, Chris On Thu, Mar 12, 2009 at 9:07 AM, SARA1232007 <cyl_axis@...> wrote: > > Hi, > > In wsrf example, it seems that WSResource instances are assembled into > ServiceGroup automatically. Can anyone tell me how this is done and which > java class is reponsible for this? > > Thanks. > > SARA > -- > View this message in context: http://www.nabble.com/Questions-about-wsrf-example-tp22471234p22471234.html > Sent from the Muse - Dev mailing list archive at Nabble.com. > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: muse-dev-unsubscribe@... > For additional commands, e-mail: muse-dev-help@... > > --------------------------------------------------------------------- To unsubscribe, e-mail: muse-dev-unsubscribe@... For additional commands, e-mail: muse-dev-help@... |
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Re: Questions about wsrf exampleIf I remember well, in the mentioned example, there's a thread that periodically is creating a resource member. The service group will qualify that resource as a group member.
There's no a direct / explicit link between the resource and the group...the membership rules are defined at RMD level. For example, the following is an extract of my service group resource RMD : <Property name="wsrf-sg:MembershipContentRule" modifiability="read-only" mutability="mutable"> <StaticValues> <wsrf-sg:MembershipContentRule MemberInterface="qman:QManWsResourcePortType"/> </StaticValues> </Property> That property states that all resources that will be created will be part of this service group only if they have the mentioned interface (port type). Obviously there are a lot of things that you can use in order to specify membership rules... you can find a better explanation about that here: http://docs.oasis-open.org/wsrf/2004/06/wsrf-WS-ServiceGroup-1.2-draft-02.pdf Note that I'm not part of Muse developemnt team so what I'm writing is what I understood browsing / using the module. As I see this is what happens 1) a resource is created using Resource resource = resourceManager.createResource(<resource name>); ... ... ... resourceManager.addResource(resource.getEndpointReference(), resource); 2) ResourceManager informs all resource manager listeners about this event using ResourceManagerListener.resourceAdded 3) One of the register listeners is the SimpleServiceGroup that is doing what I described above... Hope it helps... Andrea 2009/3/12 SARA1232007 <cyl_axis@...>
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Re: Questions about wsrf exampleSorry, Chris answer is obviously more precise...I didn't see that because I'm writing... :)
Regards, Andrea 2009/3/12 Andrea Gazzarini <a.gazzarini@...> If I remember well, in the mentioned example, there's a thread that periodically is creating a resource member. The service group will qualify that resource as a group member. |
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