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RE: wdebug instruction causes XLB slave error acknowledge interrupt on MCF547X.

by Seymour David-ra2693 :: Rate this Message:

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Ouch...just got everything put away!  That serves me right for once trying to keep a clean office.  Lesson learned.  Thx!!
 
Ok...re-ran with following code:
dBUG> di 20000
00020000: 2C80                 MOVE.L    D0,(A6)
00020002: 0002                 DC.W      0x0002
00020004: 0000                 DC.W      0x0000
00020006: 0000                 DC.W      0x0000
00020008: 207C 0002 0000       MOVEA.L   #0x00020000,A0
0002000E: 4E71                 NOP
00020010: 4E71                 NOP
00020012: FBD0 0003            WDEBUG    (A0)
00020016: 4E71                 NOP
00020018: 4E71                 NOP
0002001A: 227C 1000 0248       MOVEA.L   #0x10000248,A1
00020020: 2211                 MOVE.L    (A1),D1
00020022: 4E71                 NOP
00020024: 4E71                 NOP
00020026: 4E4F                 TRAP      #0x0F
00020028: 37FE                 DC.W      0x37FE
dBUG> rm pc 20008
dBUG> go
dBUG> rd
PC: 00020028 SR: 2004 [t.Sm.000...xnZvc]
An: 00020000 10000248 00000000 00000000 00000000 00000000 00000000 03FFFFF8
Dn: 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000
dBUG>
 
Register D1 is zero so bit 8 is not setting.
Anything else for me to try?
Regards,
David
 
David E Seymour

http://www.freescale.com/coldfire

 


From: coldfire-bounce@... [mailto:coldfire-bounce@...] On Behalf Of nop head
Sent: Tuesday, April 07, 2009 4:11 PM
To: Seymour David-RA2693
Subject: Re: [ColdFire] wdebug instruction causes XLB slave error acknowledge interrupt on MCF547X.

Hi David,
  Yes I think it kills my PSTCLK, but why does it generate an XLB interrupt? Can you look at the XLB registers as see if the status register has bit 8 set.

Chris

2009/4/7 Seymour David-RA2693 <David.Seymour@...>
Hi Chris,
I did a simple test using the M5474EVB Lite board running dBUG ROM monitor:
dBUG> di 20000
00020000: 2C80                 MOVE.L    D0,(A6)
00020002: 0002                 DC.W      0x0002
00020004: 0000                 DC.W      0x0000
00020006: 0000                 DC.W      0x0000
00020008: 267C 0002 0000       MOVEA.L   #0x00020000,A3
0002000E: 4E71                 NOP
00020010: FBD3 4E71            WDEBUG    (A3)
00020014: 4E71                 NOP
00020016: 4E71                 NOP
00020018: 4E71                 NOP
0002001A: 4E71                 NOP
0002001C: 4E71                 NOP
0002001E: 4E4F                 TRAP      #0x0F
00020020: 4E71                 NOP
00020022: 4E71                 NOP
00020024: 4E71                 NOP
 
I set the PC to 0x20008 and issued "go" command.
Watching PSTCLK with oscope, it is running be default.  After executing the above code, it is low.
So I'm seeing it work OK.
Regards,
David
 
David E Seymour
 


From: coldfire-bounce@... [mailto:coldfire-bounce@...] On Behalf Of nop head
Sent: Tuesday, April 07, 2009 9:27 AM
To: Seymour David-RA2693
Subject: [ColdFire] wdebug instruction causes XLB slave error acknowledge interrupt on MCF547X.

I want to disable the PST signals, when not debugging, to reduce RF emissions. I used the following code successfully in an MCF537X project, but when I use it on a V4 processor I get an interrupt from the XLB arbiter.

csr_data       dc.w    0010110010000000b       ;CSR
                   dc.w    2,0,0                   ;PCD
...
                lea     csr_data,a0
                dc.w    1111101111010000b     ;wdebug.l a0
                dc.w    0000000000000011b

My assembler doesn't support wdebug, hence the hand coded dc.w stuff. All the code does is set the PCD bit in the BDM CSR register.

The fault address is csr_data + 4, i..e. half way through the data. The fault is a slave error acknowledge. The data is correctly aligned on a four byte boundary and is certainly accessible by normal instructions.

Anybody know what is going on here?

TIA, Chris

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