So I guess the 'best' workaround would be to do something like below?
template<typename T>
void disconnect (void (T::*pMemFunc)(void), T& rObj, VoidSignal& rSig)
{
rSig.disconnect(VoidSlot(pMemFunc, rObj));
}
Thanks for the help.
-----Original Message-----
From:
boost-users-bounces@...
[mailto:
boost-users-bounces@...]On Behalf Of Steven Watanabe
Sent: Tuesday, July 07, 2009 9:42 AM
To:
boost-users@...
Subject: Re: [Boost-users] [Signals2] Signal disconnect wrapper won't
work
AMDG
Marc dela Cruz wrote:
> Hopefully this is not another simple oversight on my part but I have code
like below and the disconnect wrapper does not work.
>
> Thanks.
>
> typedef boost::signals2::signal<void ()> VoidSignal;
> typedef VoidSignal::slot_type VoidSlot;
> class x{
> public:
> void somefuncA()
> {
> cerr << "Bada bing" << endl;
> }
> void somefuncB()
> {
> cerr << "Bada boom " << endl;
> }
> };
>
>
> void disconnect(VoidSlot const& rF, VoidSignal& rSig)
> {
> rSig.disconnect(rF); //won't compile
> //rSig.disconnect(&rF); //compiles but doesn't disconnect
> }
>
>
> int main()
> {
> x myX;
> VoidSignal sig;
> sig.connect(VoidSlot(&x::somefuncB, &myX));
> disconnect(VoidSlot(&x::somefuncB, &myX, sig); //doesn't work/compile
as expected
> disconnect(boost::bind(&x::somefuncB, &myX, sig); //doesn't
work/compile either
> sig(); // will still invoke somefuncB
> return 0;
> }
>
Ignoring all the minor syntax errors, my guess is that
the basic problem is
http://www.boost.org/doc/html/function/faq.html#id1877737In Christ,
Steven Watanabe
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