Re: 1730-year vs. 334-yr cycle RE: 334-year cycle from Revision of Two Gear/Two Peg Lunisolar Device

Dear Brij and Calendar People

For the 1730-year cycle Brij calculated and Mean Lunation =29.5307286068  (29^d 12^h 44^m 14^s.95). This is not accurate enough to make the 1730-year cycle worth considering as a lunisolar cycle.

The number of years in it is not divisible by six, so it cannot be obtained by a  divide-by-six leap week rule (but 3*1730=5190 year can).

Karl

10(09(02 till noon

Karl, Tom Peters CC, sir:
My investigation has led me to 1730-year cycle is a combination of my (7*128)+834 =1730-year cycle. 
>> > This will usually be one every 19 years, but after the small peg
> > has moved, it'll occur again after just 11 years. This would then
> > give rise to a 334-year cycle.
334-year cycle can be utilised, with 19-year & 11-year cycles as:  
1. (5*334)+(2*19)+(2*11)  i.e. [334,19, 334,11, 334, 11, 334, 19 & 334] making 1730-years to start the next cycle; and
2. (13*128)+(6*11) i.e. [(2*128), 11, (2*128), 11, (2*128), 11, (2*128), 11, (2*128), 11, (2*128), 11 & 128]-years starting the next cycle.
As pointed earlier, 1730-year cycle, to me appear be the smallest luni-solar cycle, that can utilise 128-year cycle & 334-years cycles fixing "YEAR 0000" which is 15*128 is automatic in continuation. Current year 2009 is 23rd of 3rd 128-year cycle FOR 2nd cycle of 1730-years, making start year at Y1920; as well at 'Year 0000'. The 1730-year cycle has:

1730-yrs/21397.101Ln (631868.988 days);  90267 weeks;             Mean Year=365.2421965318            (365^d 5^h 48^m 45^s.78) and Mean Lunation =29.5307286068  (29^d 12^h 44^m 14^s.95). MY=631869/1730 =7*(52+1/6+56/5190) =365.242196531792 days , can be obtained using div.six(6) plan.

Regards,
Brij Bhushan Vij

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> Date: Fri, 22 May 2009 13:27:26 +0100
> From: karl.palmen@...
> Subject: Re: 334-year cycle from Revision of Two Gear/Two Peg Lunisolar Device
> To: CALNDR-L@...
>
> Dear Tom and Calendar People
>
> Comments below.
>
> -----Original Message-----
> From: East Carolina University Calendar discussion List
> [mailto:CALNDR-L@...] On Behalf Of Tom Peters
> Sent: 22 May 2009 09:22
> To: CALNDR-L@...
> Subject: Re: 334-year cycle from Revision of Two Gear/Two Peg Lunisolar
> Device
>
> Op 21-mei-2009, om 14:00 heeft Palmen, KEV (Karl) het volgende
> geschreven:
>
> > Dear Victor and Calendar People
> >
> > This revision can be modified simply to give a 334-year cycle.
> >
> > Instead of moving the peg(s) every 19 years (when the marked teeth
> > meet), move the peg(s), when the marked tooth of the sun wheel
> > meets the short peg.
> > This will usually be one every 19 years, but after the small peg
> > has moved, it'll occur again after just 11 years. This would then
> > give rise to a 334-year cycle.
> >
> > The 11 years have 11 rotations of the sun wheel 11*235=2585 teeth
> > equal to 136 rotations of the moon wheel plus one tooth from the
> > small peg move, which is 136*19+1=2585 teeth.
>
> Isn't this the traditional saltus lunae, once every 19 years;
> and an additional one to correct the Metonic circle by re-syncing the
> Sun and Moon after (17+11) years?
>
> No. And also the correction would remove a saltus lunae not add it.
>
> For a saltus lunae you need different gear wheels: A moon wheel of 30
> teeth and a sun wheel of 371 teeth. The moon wheel is driven one tooth
> per day plus an extra tooth in each 29-day lunation. The Saltus lunae is
> then the slipping of the moon wheel one tooth against the sun wheel. It
> can be implemented by turning the moon wheel 136 times and one tooth
> (4081 teeth), which turns the sun wheel exactly 11 times (11*371=4081
> teeth).
>
> An arrangement of pegs in 19 holes could be used to time the Saltus
> lunae. One possibility is to have a long peg that moves annually and a
> short peg that moves once every 12 years in the same direction. Also
> both pegs can occupy the same hole. Whenever this happens, we have a
> Saltus lunae, but never in a year that the short peg moves. This would
> give a 6840-year cycle.
>
> My lunisolar spreadsheets
> http://www.the-light.com/cal/kp_Lunisolar_xls.html indicate how many
> Saltus lunae any given cycle requires. For the 334-year cycle it is 16.
> For an A-year cycle of B leap months, it is 30*B - 11*A.
>
> Karl
>
> 10(08(28
>
> --
> Scanned by iCritical.
>

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