« Return to Thread: 13 x 353 = 4589-year lunisolar cycle
Re: 2 x 353 = 706-year and 13 x 353 = 4589-year lunisolar cycles
by Karl Palmen
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Dear Irv and Calendar People
The 13x353-year cycle has 1,676,097 days and the 11x353-year
cycle has 257,861 days fewer.
So twenty 13x353 plus three 11x353 has 23x1,676,097 – 3x257,
861 = 37,776,648 days, which is the number Irv calculates for the 293x353.
Also 37,776,648=294*364*353 as expected.
This verifies my guess based on the number of years.
Karl
10(08(10 till noon
PS: I meant 13x353 when I typed 1x353.
From: East Carolina University Calendar
discussion List [mailto:CALNDR-L@...] On Behalf Of Irv
Bromberg
Sent: 01 May 2009 22:35
To: CALNDR-L@...
Subject: Re: 2 x 353 = 706-year and 13 x 353 = 4589-year lunisolar
cycles
On
2009 May 1, at 12:14 , Palmen, KEV (Karl) wrote:
I note that Irv stated that this 1x353-year cycle has a mean year very close to that of the 293-year cycle. There exists a 293x353-year cycle with exactly the same mean year, I expect it would be made up of twenty 13x353-year cycles and just three 11x353-year cycles.
Irv
replies: In order for the 293*353=103,429 year cycle to have a
mean year of 365+71/293 days there would have to be 37,776,648 days
= 5,396,664 weeks in the cycle.
With
293*4366=1,279,238 months the mean month would be 37776648/1279238 =
29+339373/639619 days = 29d 12h 44m 2+413002/639619s (the fraction is just shy
of 2/3 of a second), which is very accurate for the present era.
If
one takes the ratio of the mean year to the mean month:
(365
+ 71/293) / (29 + 339373/639619) = 4366 / 353
Scanned by iCritical.
« Return to Thread: 13 x 353 = 4589-year lunisolar cycle
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