Re: Alternating Periodic Sequences

Dear Helios and Calendar People

If for this we had a mean cell yerm of exactly 246 days, then we'd have
a 3-yerm cycle of 491 cells lasting 738 days. 243 of these 3-yerm cycle
would make 491 years of 179,334 days with a mean year of exactly 365
119/491 days about 365.24236 days.

The mean month is 334/(243*17) this mean year (738*334/(491*17)) so is
exactly 29 4429/8347 days about 29.5306098 days.
The resulting 8347-month cycle forms a simple lunar yerm cycle of 511
lunar yerms (one lunar yerm era).

I'll leave it the Helios and other calendar people to investigate the
case were the mean cell yerm has exactly 246 3/34 days.

Karl

10(08(11 till noon

-----Original Message-----
From: East Carolina University Calendar discussion List
[mailto:CALNDR-L@...] On Behalf Of Helios
Sent: 05 May 2009 16:36
To: CALNDR-L@...
Subject: Re: Alternating Periodic Sequences

Dear Karl P and Calendar People

This might be an improvement. There are notable properties of the cell
that
is set to 1 / 243rd year when applied to the mean year of the 95-year.
By
first using the year

Y = 365 & 23 / 95 days

There are 23065 cells in the 95-year cycle of 34698 days. With
1 cell = 1 & 3871 / 7695 days = 1 / 243rd year

We are equipt to evaluate

mean yerm of 243rds = 1 / [ 2 - ( 729 / Y ) ] = X

X = cell-yerm = 246 & 4 / 47 days

So there are 141 cell-yerms in the 95-year cycle of 34698 days.
------------------------------------------------------------------------
-

Now it may be noted that

334 cells = 17 months

4131 months = 334 years

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