Re: Custom HTTP response

> Thank you for reply.
> I've raised the exception like:
>       try:
>            raise Exception("Session expired")
>        except Exception:
>            return Exception
>
> But pyAMF caught my exception like:
>
> 2009-06-17 15:21:13,672 DEBUG  
> [pyamf.remoting.gateway.twisted.TwistedGateway.0x2211750] AMF  
> Response: <Response status=/onResult><AcknowledgeMessage  body=<type  
> 'exceptions.Exception'> timestamp=1245266473 destination=None  
> clientId='cdfc3d99-7fe2-4017-a2c0-07ed13776e5c' headers={}  
> timeToLive=0 messageId='386a143f-72f3-4687-8f36-a6800dcd914c'  
> correlationId=u'85C5E409-974F-1AA9-86A6-F0517212A761' /></Response>
> 2009-06-17 15:21:13,678 ERROR  
> [pyamf.remoting.gateway.twisted.TwistedGateway.0x2211750] <class  
> 'pyamf.EncodeError'>: Callables cannot be serialised
>
>
> Where am I wrong ?
> Appreciate y help.
>
>
>
>
>
> Quoting "Nick Joyce" <nick@...>:
>
>> If you want to return an error in remoting, just raise an exception.
>> The message of the exception will be the description in the error
>> response.
>>
>> Hope that helps.
>>
>> Nick
>>
>> On 16 Jun 2009, at 19:37, vitaly@... wrote:
>>
>>> hi all,
>>> 1.is there any possibility to send( and how :-)) ) custom HTTP  
>>> response back to client request?
>>> Something like:
>>> return(remote.Response(response, status=remoting.STATUS_ERROR))
>>>
>>> 2.how can I set the custom response to some particular HTTP code  
>>> and message(body)?
>>>
>>> Appreciate the help.
>>>
>>> _______________________________________________
>>> PyAMF users mailing list - users@...
>>> http://lists.pyamf.org/mailman/listinfo/users
>>
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>
>
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