Re: Groovy way to format BigDecimal with thousands separator [SOLUTION]

[Michael Potter-3]

On Tue, Oct 27, 2009 at 10:51 AM, Michael Potter <pottmi@...> wrote:

> On Tue, Oct 27, 2009 at 10:46 AM, Jochen Theodorou <blackdrag@...> wrote:
>> Michael Potter schrieb:
>>>
>>> Groovy Crew,
>>>
>>> What are my options to format a BigDecimal with commas?
>>>
>>> I see code using DecimalFormat( "#,###,###,##0.00" ), but
>>> DecimalFormat requires the BigDecimal be converted to double and I do
>>> not want to take the chance of changing the original number.
>>
>> DecimalFormat has also an Object taking format method you can use here
>>
>> bye blackdrag
>>
>> --
>> Jochen "blackdrag" Theodorou
>> The Groovy Project Tech Lead (http://groovy.codehaus.org)
>> http://blackdragsview.blogspot.com/
>>
>
>
> Jochen,
>
> Are you saying that the DecimalFormat(Object) constructor will take a
> BigDecimal?
>
> --
> Michael Potter
>

Thank you Jochen,

This worked:

BigDecimal bd = new BigDecimal("123456.798")
def df = new java.text.DecimalFormat("#,###,###,##0.00" )
String s = df.format(bd)
assert s == "123,456.80"

Sorry about the hard coded types, but I want to make sure that the
numbers are not converted to double.

--
Michael Potter

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[Russel Winder-4]

On Tue, 2009-10-27 at 11:19 -0400, Michael Potter wrote:
[ . . . ]
> BigDecimal bd = new BigDecimal("123456.798")
> def df = new java.text.DecimalFormat("#,###,###,##0.00" )
> String s = df.format(bd)
> assert s == "123,456.80"
>
> Sorry about the hard coded types, but I want to make sure that the
> numbers are not converted to double.

All floating point literals and values are BigDecimal by default -- you
actually have to work very hard to get doubles in Groovy.

        def bd = 123456.798
        assert bd.class == BigDecimal
        def df = new java.text.DecimalFormat ( '#,###,###,##0.00' )
        def s = df.format ( bd )
        assert s == "123,456.80"

--
Russel.
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