:|
if i want link 3,
$result = mysql_query("SELECT address FROM db.links WHERE link_id=3");
$foo = mysql_fetch_assoc($result);
echo '<a href="'.$foo['address'].'">this is link 3</a>';
On 3/7/07, StainOnRug <
StainOnRug@...> wrote:
>
>
> Hello.. I searched for an answer on the simple quesiton but I am only
> finding
> complex answers... I simply just want to add a link in my database so when
> my results display you can see the information.. and when they click the
> link it takes them to the webpage of the article. I tried inserting
> examplesite.com User sees this text but when the results page shows.. it
> doesnt show the hyperlink.. Thank you all very much!
>
>
>
> -Darren
>
> Thanks again!
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> View this message in context:
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