Daniel Brown wrote:
>> if(!isset($key=='1')) //caused parse error
> That's because isset() isn't able to eval() an expression.
Got it, I see the mistake now.
> Remove the !isset() part, or the =='1' part and that will remove
> the parse error.
I changed it to if(!isset($key)) and you were right, the parse error
went away. This change seems to have no effect on access code logins
(I'm able to log in, as expected) or IP-authenticated logins (I still
cannot log in, even though my IP is in the MySQL db).
Reese
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