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Re: Problem in designing pipelines

by Patricia Déchandol :: Rate this Message:

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I found the issue !
It was a wrong namespace declaration in the XSL of the first pipeline.
The generated XML was containing this namespace on some nodes and it was a problem.
The generated content was not interpreted as XML.
It's solved.
Thanks Robby another time for your help.

Patricia

Le 23 mars 2012 à 17:03, Robby Pelssers a écrit :

One thing.  By default <map:transform src="exist/xsl/expotree2html.xsl"/> uses Xalan XSLT processor.  So you can’t use XSLT 2.0 unfortunately.  If however you  want to use Saxon here are some instructions:
 
<image001.png>
 
Robby
 
 
From: Patricia Déchandol [mailto:pdechandol@...] 
Sent: Friday, March 23, 2012 4:59 PM
To: users@...
Subject: Re: Problem in designing pipelines
 
Ok, thanks for this explanations.
I says to me that the error must be due to something wrong either in the execution of the first pipeline or in the XSL if the second pipeline.
Thanks Robby.
 
Patricia
 
Le 23 mars 2012 à 16:55, Robby Pelssers a écrit :


The default generator @type is the XML file generator. So if cocoon://{1}/tree-expo-get-children returns XML you don’t need to specify a type on the generator.
 
Robby
 
From: Patricia Déchandol [mailto:pdechandol@...] 
Sent: Friday, March 23, 2012 4:54 PM
To: users@...
Subject: Re: Problem in designing pipelines
 
Yes, I understood this point I think.
But which the of generator must I call there ? No particular type ?
It may like this ?
Because if it's supposed to work, the error I meet when I use a generator must be due to something else.
 
Patricia
 
Le 23 mars 2012 à 16:04, Robby Pelssers a écrit :



You should not use map:read but map:generate when you want to do further processing.    
 
              <map:match pattern="*/tree-expo-content">
                           <map:generate src="cocoon://{1}/tree-expo-get-children"/>
                           <map:transform src="exist/xsl/expotree2html.xsl"/>
                           <map:serialize type="html"/>
                     </map:match>
 
 
From: Patricia Déchandol [mailto:pdechandol@...] 
Sent: Friday, March 23, 2012 3:31 PM
To: users@...
Subject: Problem in designing pipelines
 
Hi everybody,
 
I have a problem understanding how to write my pipelines.
 
I have a first pipeline :
 
                     <map:match pattern="*/tree-expo-get-children">
                           <map:generate type="xquery" src="exist/xq/get-children-rubriques.xq">
                                  <map:parameter name="parentid" value="{1}" />
                           </map:generate>
                           <map:transform src="exist/xsl/get-children-rubriques.xsl"/>
                           <map:serialize type="xml"/>
                     </map:match>
 
This pipeline works perfectly resulting a XML tree.
I would want to applicate another XSL to the resulting XML.
 
You will say that I just have to put another <map:transform> after the first one.
But I can't, because of a particularity :  the call to this first pipeline is iterative : the transform call this same pipeline.
 
So I thought about writing another :
 
                     <map:match pattern="*/tree-expo-content">
                           <map:read src="cocoon://{1}/tree-expo-get-children"/>
                           <map:transform src="exist/xsl/expotree2html.xsl"/>
                           <map:serialize type="html"/>
                     </map:match>
 
The problem is that when I execute this pipeline, I get the XML document resulting from the map:read but the transform is not performed.
If I put a map:generate replacing the map:read, the execution fails with an error in declaration of my XSL.
 
I don't understand how I can chain these transforms.
Which generator could work ?
 
Thanks for your help
 
Patricia


 « Return to Thread: Problem in designing pipelines