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On Thu, Jun 18, 2009 at 2:43 PM, ilyes
<ilyesnaili@...> wrote:
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Jasypt Users List
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i have a problem when i run my application inside lunix but it work so well
inside windows envirnoment
when i run my application inside linux it show me that i cant find the
envrinoment variable that i use to crypte my password but when i make echo
$myVariable it show me the correct value..
Does someone can help me!!! sorry for my bad english :)
squeeze the project to a .web archive and with all jasypt jars and dependecies in the .ear or .war or in the jdk ext directory are some ways I got it. echo depends on system path and java has its own path and classpath. We can help even better if you paste the error message. Putting the jasypt jar in the java classpath should work. Worst case, you may inspect my configuration 100 % linux jasypt authenticating with no jasypt failure uptime > 100 days unbroken.
with regards and thanks to all jasypt R&D, contributors, collaborators and supporters
_________
NiklasRTZ.
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