Re: PyAMF 0.4.2 - Code Server.Call.Failed is already registered / Django Integration

> Hi,
>
> Is this in a production environment ?
>
> I ask because it sounds like pyamf is being reloaded. If this is the  
> case then this is a bug and a ticket should be created.
>
> Cheers,
>
> Nick
>
> On 13 Jul 2009, at 15:48, Piero Campanelli wrote:
>
>> Hi,
>> when I use PyAMF 0.4.2 with Django I receive following error:
>> Code Server.Call.Failed is already registered
>> It seems problem is in the following:
>> pyamf/__init__.py
>> in method add_error_class(klass,code). If I comment these lines:
>>  if code in ERROR_CLASS_MAP.keys():
>>       raise ValueError('Code %s is already registered' % (code,))
>> it works.
>>
>> def add_error_class(klass, code):
>>   """
>>   Maps an exception class to a string code. Used to map remoting  
>> C{onStatus}
>>   objects to an exception class so that an exception can be built to
>>   represent that error::
>>
>>       class AuthenticationError(Exception):
>>           pass
>>
>>   An example: C{add_error_class(AuthenticationError, 'Auth.Failed')}
>>
>>   @type code: C{str}
>>
>>   @raise TypeError: C{klass} must be a C{class} type.
>>   @raise TypeError: Error classes must subclass the  
>> C{__builtin__.Exception} class.
>>   @raise ValueError: Code is already registered.
>>   """
>>   if not isinstance(code, basestring):
>>       code = str(code)
>>
>>   if not isinstance(klass, (type, types.ClassType)):
>>       raise TypeError("klass must be a class type")
>>
>>   mro = util.get_mro(klass)
>>
>>   if not Exception in mro:
>>       raise TypeError('Error classes must subclass the  
>> __builtin__.Exception class')
>>
>>   if code in ERROR_CLASS_MAP.keys():
>>       raise ValueError('Code %s is already registered' % (code,))
>>
>>   ERROR_CLASS_MAP[code] = klass
>>
>>
>> _______________________________________________
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>> http://lists.pyamf.org/mailman/listinfo/users
>
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