Re: Testing the significant difference in Proportions

Note also that there is a PROPOR extension command available from SPSS Developer Central (www.spss.com) that will construct various confidence intervals for proportions.  It requires at least version 16 and the Python plugin, but no Python knowledge is required to use it.

-----Original Message-----
From: SPSSX(r) Discussion [mailto:SPSSX-L@...] On Behalf Of Bruce Weaver
Sent: Monday, July 06, 2009 5:27 AM
To: SPSSX-L@...
Subject: Re: [SPSSX-L] Testing the significant difference in Proportions

Jims More wrote:
You can always roll your own, like this:

data list list / cat (f2.0) x N (2f6.0).
begin data
1 40 100
2 30 100
3 80 100
4 40 100
5 34 100
end data.

compute p = x/N.
compute se = SQRT( p*(1-p)/N).
compute z = (p - .5)/se.
compute pvalue = 2*(1-(CDF.NORMAL(abs(z),0,1))) .
format se pvalue (f5.3).
list.

You'll have to fill in the correct values of X and N, of course.


-----
--
Bruce Weaver
bweaver@...
http://sites.google.com/a/lakeheadu.ca/bweaver/
"When all else fails, RTFM."

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