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Re: Testing the significant difference in Proportions
by García-Granero
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Hi Eins:
You don't need a special syntax to achieve that task. You have to split
your file by the categorical predictor and then run a goodness of fit
test (ANALYZE -> NON PARAMETRIC -> CHI-SQUARE) for the Yes/No variable
with equal expected values.
That's it.
Marta
Eins Bernardo wrote:
> Hi Jims, Bruce, et al,
>
>
Can someone translate the syntax of Bruce into syntax that do the same
but for SPSS data file with variables(predictor and dependent) in the
columns
> Jims More wrote:
> >
> > I have two categorical variables. One is the response variable, a
> yes/no
> > variable. The other is a categorical predictor variable which has 5
> > categories. The proportion table of the gathered data (n=5000)
> looks like
> > as follows:
> >
> > Row % of Yes Response Row % of No
> > Response
> > Category1 .40 .60
> > Category2 .30 .70
> > Category3 .80 20
> > Category4 .40 .60
> > Category5 .34 .66
> >
> > How to test using SPSS if the proportions of Yes and No are
> significantly
> > equal for each category?
> >
> > Thank you for any help.
> > Jims
> >
> Bruce replied:
>
> You can always roll your own, like this:
>
> data list list / cat (f2.0) x N (2f6.0).
> begin data
> 1 40 100
> 2 30 100
> 3 80 100
> 4 40 100
> 5 34 100
> end data.
>
> compute p = x/N.
> compute se = SQRT( p*(1-p)/N).
> compute z = (p - .5)/se.
> compute pvalue = 2*(1-(CDF.NORMAL(abs(z),0,1))) .
> format se pvalue (f5.3).
> list.
>
> You'll have to fill in the correct values of X and N, of course.
> .
>
> Thank you.
> Eins
>
>
> ------------------------------------------------------------------------
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--
For miscellaneous SPSS related statistical stuff, visit:
http://gjyp.nl/marta/
=====================
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You don't need a special syntax to achieve that task. You have to split
your file by the categorical predictor and then run a goodness of fit
test (ANALYZE -> NON PARAMETRIC -> CHI-SQUARE) for the Yes/No variable
with equal expected values.
That's it.
Marta
Eins Bernardo wrote:
> Hi Jims, Bruce, et al,
>
>
Can someone translate the syntax of Bruce into syntax that do the same
but for SPSS data file with variables(predictor and dependent) in the
columns
> Jims More wrote:
> >
> > I have two categorical variables. One is the response variable, a
> yes/no
> > variable. The other is a categorical predictor variable which has 5
> > categories. The proportion table of the gathered data (n=5000)
> looks like
> > as follows:
> >
> > Row % of Yes Response Row % of No
> > Response
> > Category1 .40 .60
> > Category2 .30 .70
> > Category3 .80 20
> > Category4 .40 .60
> > Category5 .34 .66
> >
> > How to test using SPSS if the proportions of Yes and No are
> significantly
> > equal for each category?
> >
> > Thank you for any help.
> > Jims
> >
> Bruce replied:
>
> You can always roll your own, like this:
>
> data list list / cat (f2.0) x N (2f6.0).
> begin data
> 1 40 100
> 2 30 100
> 3 80 100
> 4 40 100
> 5 34 100
> end data.
>
> compute p = x/N.
> compute se = SQRT( p*(1-p)/N).
> compute z = (p - .5)/se.
> compute pvalue = 2*(1-(CDF.NORMAL(abs(z),0,1))) .
> format se pvalue (f5.3).
> list.
>
> You'll have to fill in the correct values of X and N, of course.
> .
>
> Thank you.
> Eins
>
>
> ------------------------------------------------------------------------
> Have a new Yahoo! Mail account?
> <http://us.rd.yahoo.com/SIG=11dea1p2c/**http%3A%2F%2Fwww.trueswitch.com%2Fyahoo-ph>
> Kick start your journey by importing all your contacts!
--
For miscellaneous SPSS related statistical stuff, visit:
http://gjyp.nl/marta/
=====================
To manage your subscription to SPSSX-L, send a message to
LISTSERV@... (not to SPSSX-L), with no body text except the
command. To leave the list, send the command
SIGNOFF SPSSX-L
For a list of commands to manage subscriptions, send the command
INFO REFCARD
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