hi ..
There is a reply to you please find it and revert me back
-misbah
I didnt got very clearly what you actually did. But i guess you did faced some problem to work with work queue ( Bottom half of the handler ) I suggest you with an example code so that you could try with it and hope your doubt would get cleared.
/* work queue register and initialize */
static DECLARE_WORK(queue_name,(void *)func_name,func_arq_ptr);
eg :-
static DECLARE_WORK(my_queue,(void *)my_func,NULL);
/* In the Interrupt handler you need to call the bottom half of the function */
schedule_work(&my_queue);
/* The function defination is like this */
void my_func(void)
{
printk(" Hello from kernal land \n");
}
I hope this example will make your code to work for you , for any clarification please let me know
thanks
Xin Zhao wrote:
I tried to schedule some work in an softirq handler. The way I did is
as follows:
I use create_workqueue to initialize a workqueue "vrpciod_workqueue",
in the softirq, I do INIT_WORK(work, func, data), and then
queue_work(vrpciod_workqueue, work);
I think func() should be called a bit later. However, I noticed that
func() is never called by the workqueue. I don't know why.
Can soneone give me some suggestions? Many thanks!
Xin
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Re: workqueue is not working?
