TempoClock doesn't work in a Dictionary?

[Juan Gabriel Alzate Romero]

Dear list,

I'm a little bit troubled why this code won't work (it works, but not as desired)

(

q = ();

q.clock = TempoClock(5);

Pbindef(\a, \dur, 1);

Pbindef(\b, \dur, 0.5);

Pbindef(\c, \dur, 0.25);

Pbindef(\d, \dur, 0.125);

Ptpar([

0, Pdef(\a),

10, Pdef(\b),

15, Pdef(\c),

30, Pdef(\d),

]).play(clock: q.clock);

)

---but this one does---

(

t = TempoClock(5);

Pbindef(\a, \dur, 1);

Pbindef(\b, \dur, 0.5);

Pbindef(\c, \dur, 0.25);

Pbindef(\d, \dur, 0.125);

Ptpar([

0, Pdef(\a),

10, Pdef(\b),

15, Pdef(\c),

30, Pdef(\d),

]).play(clock: t);

)

Now, does this problem has to do woth Ptpar? or with using the TempoClock on a dictionary?

Thanks.

-Juan

[Batuhan Bozkurt]

Hi Juan,

Can't see what you are trying to achieve here, and I'm not very experienced with patterns, but this might keep you going:

First of all, q in your non working example is not a dictionary but an Event.

q = ();

q.class;

When you assign a key called event, it is not added to the event, probably because it is interpreted as something else (not really sure about the mechanics behind it):

q =  ();

q.clock = TempoClock(5);

q.clock; //nil

Instead use a different name for your clock:

q = ();

q.whatever = TempoClock(5);

q.whatever; //a tempo clock

And use that:

.....]).play(clock: q.whatever);

Hope that helps...

B.B.

On Apr 18, 2009, at 12:24 PM, Juan Gabriel Alzate Romero wrote:

Dear list,

I'm a little bit troubled why this code won't work (it works, but not as desired)

(

q = ();

q.clock = TempoClock(5);

Pbindef(\a, \dur, 1);

Pbindef(\b, \dur, 0.5);

Pbindef(\c, \dur, 0.25);

Pbindef(\d, \dur, 0.125);

Ptpar([

0, Pdef(\a),

10, Pdef(\b),

15, Pdef(\c),

30, Pdef(\d),

]).play(clock: q.clock);

)

---but this one does---

(

t = TempoClock(5);

Pbindef(\a, \dur, 1);

Pbindef(\b, \dur, 0.5);

Pbindef(\c, \dur, 0.25);

Pbindef(\d, \dur, 0.125);

Ptpar([

0, Pdef(\a),

10, Pdef(\b),

15, Pdef(\c),

30, Pdef(\d),

]).play(clock: t);

)

Now, does this problem has to do woth Ptpar? or with using the TempoClock on a dictionary?

Thanks.

-Juan

[Juan Gabriel Alzate Romero]

Hi, and thanks for your answer.

Hi Juan,

Can't see what you are trying to achieve here, and I'm not very experienced with patterns, but this might keep you going:

Justwanted to start different Ptpars in different tempi, bus as the 1th Ptpar didn't worked I had to ask the list.

First of all, q in your non working example is not a dictionary but an Event.

q = ();

q.class;

I see.  I always used the "( )" as an IdentityDictionary but I wasn't aware of the mechanics in the background.

When you assign a key called event, it is not added to the event, probably because it is interpreted as something else (not really sure about the mechanics behind it):

q =  ();

q.clock = TempoClock(5);

q.clock; //nil

Instead use a different name for your clock:

q = ();

q.whatever = TempoClock(5);

q.whatever; //a tempo clock

And use that:

.....]).play(clock: q.whatever);

That works... hm... funny the name "clock" won't work.  I guess I'll just name it "myClock" ;-)  Anyway I need different Clocks, so I'll just give them a different name than "clock"

Hope that helps...

Totally :-)  Just still wondering why the name "clock" wont work.  But anyway, I can do now what I wanted.

Thanks.

Juan.

B.B.

On Apr 18, 2009, at 12:24 PM, Juan Gabriel Alzate Romero wrote:

Dear list,

I'm a little bit troubled why this code won't work (it works, but not as desired)

(

q = ();

q.clock = TempoClock(5);

Pbindef(\a, \dur, 1);

Pbindef(\b, \dur, 0.5);

Pbindef(\c, \dur, 0.25);

Pbindef(\d, \dur, 0.125);

Ptpar([

0, Pdef(\a),

10, Pdef(\b),

15, Pdef(\c),

30, Pdef(\d),

]).play(clock: q.clock);

)

---but this one does---

(

t = TempoClock(5);

Pbindef(\a, \dur, 1);

Pbindef(\b, \dur, 0.5);

Pbindef(\c, \dur, 0.25);

Pbindef(\d, \dur, 0.125);

Ptpar([

0, Pdef(\a),

10, Pdef(\b),

15, Pdef(\c),

30, Pdef(\d),

]).play(clock: t);

)

Now, does this problem has to do woth Ptpar? or with using the TempoClock on a dictionary?

Thanks.

-Juan

[Julian Rohrhuber]

>
>That works... hm... funny the name "clock" won't work.  I guess I'll
>just name it "myClock" ;-)  Anyway I need different Clocks, so I'll
>just give them a different name than "clock"

the test whether a method is unused  in an event is usually:

a = ();
a.clock = \something;

if this throws no error, then it should work actually.
--





.

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[James Harkins-2]

The warning doesn't appear here because of Object:clock_, which gobbles up the call before Event gets its hands on it.

hjh

On Apr 18, 2009, at 4:32 PM, Julian Rohrhuber wrote:

That works... hm... funny the name "clock" won't work.  I guess I'll just name it "myClock" ;-)  Anyway I need different Clocks, so I'll just give them a different name than "clock"

the test whether a method is unused  in an event is usually:

a = ();

a.clock = \something;

if this throws no error, then it should work actually.

: H. James Harkins

: jamshark70@...

: http://www.dewdrop-world.net

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