Using SOLVE - can I solve 6 equations?

[Sparky_]

Greetings -

I am trying to solve 6 equations - 5 unknowns.

I tried 3 and 3 first and it worked -

here is what I entered:

solve([ ((126.64^2)/R1) + Pfix = 23.90, ((123.64^2)/R2)+Pfix = 23.90, ((126.64^2)/R2)
 +Pfix = 24.2, (IR1^2)*R1 +V1*(522.87-IR1) = 23.9,(IR2^2)*R1 +V2*(534.09-IR2) = 23.9,
  (IR1^2)*R1 = ((126.64)^2)/R1, ((IR2^2)/R2) = ((123.64)^2/R2) ],[R1,R2,Pfix,IR1,IR2]);

Here is what I get:

`rat' replaced -23.9 by -239/10 = -23.9
`rat' replaced 16037.6896 by 465093/29 = 16037.68965517241
`rat' replaced -23.9 by -239/10 = -23.9
`rat' replaced 15286.8496 by 1727414/113 = 15286.84955752212
`rat' replaced -24.2 by -121/5 = -24.2
`rat' replaced 16037.6896 by 465093/29 = 16037.68965517241
`rat' replaced -23.9 by -239/10 = -23.9
`rat' replaced 522.87 by 52287/100 = 522.87
`rat' replaced -23.9 by -239/10 = -23.9
`rat' replaced 534.09 by 53409/100 = 534.09
`rat' replaced -16037.6896 by -465093/29 = -16037.6896551724
`rat' replaced -15286.8496 by -1727414/113 = -15286.8495575221

(%o5) []

Nothing between the brackets above - in my 3 eqs 3 unknowns I get the solution between the bracket.

Thoughts?

Thanks
Sparky_

[TheoH]

I believe you try to solve 7 equations with only 5 variables.
Usually, this will not work if you use floating point numbers.
Throw away two redundant expressions, and then if there is a solution you'll find it.

[TheoH]

I believe you try to solve 7 equations with only 5 variables.
Usually, this will not work if you use floating point numbers.
Throw away two redundant expressions, and then if there is a solution you'll find it.

[TheoH]

I believe you try to solve 7 equations with only 5 variables.
Usually, this will not work if you use floating point numbers.
Throw away two redundant expressions, and then if there is a solution you'll find it.