Nabble - Zend gdata

Re: Working with Multi-page Feeds Google Provisioning API

2009-11-17T14:27:40Z

Those were two different options (retrievePageOfUsers vs getNextLink).

So, now that you have the link, you'll retrieve that feed using:

http://framework.zend.com/apidoc/core/Zend_Gdata/Gapps/Zend_Gdata_Gapps.html#getUserFeed

Just pass in the URL into the first argument of that function and you should be all set.

As to where to store the next URL in between requests, you can probably just put it as an escaped query parameter for the link that you display on your webpage. This assumes only trusted users are able to access this web application. Otherwise, you should probably do more to protect yourself from people modifying the URL on your webpage and passing in arbitrary URLs into getUserFeed (like do server-side validation that the format/domain/path of the URL is what you expect it to be)

Cheers,

-Ryan

On Tue, Nov 17, 2009 at 2:11 PM, Hugo Leon <hugolec@...> wrote:

Thanks for your quick response Ryan.

I got the link (this is the nextLink):
https://apps-apis.google.com/a/feeds/isseg.gob.mx/user/2.0?startUsername=egomezma

But where should I put the instruction $service->retrievePageOfUsers($startUsername=null)?

I need to click somewhere in the page so I can get the next 100 users.

while ($feed !== null) {
foreach ($feed as $user) {
$user->login->username;
}
$feed = **$feed->getNextFeed();**
}

Hugo

On Tue, Nov 17, 2009 at 3:39 PM, Ryan Boyd <ryanboyd@...> wrote:

On Tue, Nov 17, 2009 at 1:30 PM, Hugo León <hugolec@...> wrote:

Hello again Ryan.

I decided to leave this issue until the end because it was difficult to
perform. I have now reached the point where this is the only thing missing
to complete the system.

I did what you suggested:

while ($feed !== null) {
foreach ($feed as $user) {
echo "<tr>";
echo "<td>".$user->login->username."</td>";
echo ""</tr>; }

* $feed = **$feed->getNextFeed();**
}

And what it does is that it shows all records of the feed exactly as
retrieveAllEntriesForFeed() instruction. But what I want to do is break them
into pages.

There's an atom:link element with a rel='next' that contains the link for the next step of results. Instead of $feed->getNextFeed(), you can instead call $feed->getNextLink()->getHref(), which will be the URL for the next step of results. You can see the format for the provisioning API-- it just uses the next username in the feed for paging.

Are there some examples for this task?

The closest examples are to retrieve 100 users starting at a particular username:
http://code.google.com/apis/apps/gdata_provisioning_api_v2.0_reference_php.html#Retrieve_100_Users_in_Domain_Example

Of course, you'll need to know the next username-- though you could always use the last username you saw and then just ignore the first result. However, I think the getNextLink method will work better.

Cheers,
-Ryan

Best regards.
Hugo

Ryan Boyd-3 wrote:
>
> When you echo out the previous and next URLs, what do you get? You won't
> be
> able to click on it and see it (because you wouldn't be sending the
> appropriate auth credentials), but you should be able to retrieve that
> feed.
>
> The following two blocks of code should be identical:
> ---
> while ($feed !== null) {
> foreach ($feed as $user) {
> echo "<tr>";
> echo "<td>".$user->login->username."</td>";
> echo ""</tr>; }
> * $feed = **$feed->getNextFeed();**
> }*----
> ---
> while ($feed !== null) {
> foreach ($feed as $user) {
> echo "<tr>";
> echo "<td>".$user->login->usern"</td>";
> echo ""</tr>; }
> * $feed = **$feed->getUserFeed($nextLink);*
> }----
>
> On Wed, Oct 21, 2009 at 4:34 PM, Hugo León <hugolec@...> wrote:
>
>>
>> Hello Ryan.
>>
>> For now I'm getting in the same manner the feed to the next page, but the
>> URL that I've got is
>>
>> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
>> and when I click it can't see the next page of the feed.
>>
>> What I do not want to do is show all the entries because we have one
>> GApps
>> domain with about 2,000 users, just as you recommended me.
>>
>> Here is the code:
>>
>> Zend_Loader::loadClass('Zend_Gdata');
>> Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
>> Zend_Loader::loadClass('Zend_Gdata_Gapps');
>> Zend_Loader::loadClass('Zend_Gdata_Feed');
>>
>> //ClientLogin
>> function getClientLoginHttpClient($user, $pass)
>> {
>> try{
>> $service = Zend_Gdata_Gapps::AUTH_SERVICE_NAME;
>> $client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass,
>> $service);
>> return $client;
>> } catch (Zend_Gdata_App_AuthException $e) {
>>
>> }
>> }
>>
>> $client = getClientLoginHttpClient($admin."@".$domain, $gappspass);
>> $gapps = new Zend_Gdata_Gapps($client, $domain);
>> $feed = $gapps->getUserFeed();
>> $previousLink = $feed->getLink("previous");
>> $nextLink = $feed->getLink("next");
>>
>> foreach ($feed as $user) {
>> echo "<tr>";
>> echo "<td>".$user->login->username."</td>";
>> echo ""</tr>;
>> }
>> if ($previousLink !== null) {
>> echo "previous url: " . $previousLink->href . " ";
>> $previousFeed = $gapps->getUserFeed($previousLink->href);
>> }
>> if ($nextLink !== null) {
>> echo "next url: " . $nextLink->href . " ";
>> $nextFeed = $gapps->getUserFeed($nextLink->href);
>> }
>>
>> Where should I put '$feedWithNextPageOfEntries = $feed->getNextFeed();' ?
>> or
>> how should I call it?.
>>
>> Thanks in advance.
>> Hugo
>>
>>
>> Ryan Boyd (Google) wrote:
>> >
>> > You probably have an existing $feed variable with the feed of results.
>> >
>> > Try:$feedWithNextPageOfEntries = $feed->getNextFeed();
>> > If you have a $service and an existing $feed and want to retrieve ALL
>> > entries (can be expensive), you can do:
>> > $feedWithAllEntries = $service->retrieveAllEntriesForFeed($feed);
>> >
>> > Cheers,
>> > -Ryan
>> >
>> > On Tue, Oct 13, 2009 at 2:56 PM, Hugo León <hugolec@...> wrote:
>> >
>> >>
>> >> Hello everyone.
>> >> I'm trying to get all users of a Google Apps domain and does it well.
>> >> But when there are domains with more than 100 users appear only the
>> first
>> >> 100, and with the function that comes into Zend website gives me the
>> link
>> >>
>> >>
>> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
>> >> ,
>> >> but obviously when I click on that link it does not work because I
>> need
>> >> authorization via ClientLogin again. And what I want to do is that it
>> >> only
>> >> shows me the next 100 users.
>> >>
>> >> How can I do this?
>> >> Thanks in advance.
>> >>
>> >> Hugo
>> >> --
>> >> View this message in context:
>> >>
>> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p25881614.html
>> >> Sent from the Zend gdata mailing list archive at Nabble.com.
>> >>
>> >>
>> >
>> >
>>
>> --
>> View this message in context:
>> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p26001897.html
>> Sent from the Zend gdata mailing list archive at Nabble.com.
>>
>>
>
>

--
View this message in context: http://old.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p26396478.html

Sent from the Zend gdata mailing list archive at Nabble.com.

Re: Working with Multi-page Feeds Google Provisioning API

2009-11-17T13:39:39Z

On Tue, Nov 17, 2009 at 1:30 PM, Hugo León <hugolec@...> wrote:

Hello again Ryan.

I decided to leave this issue until the end because it was difficult to
perform. I have now reached the point where this is the only thing missing
to complete the system.

I did what you suggested:

while ($feed !== null) {
foreach ($feed as $user) {
echo "<tr>";
echo "<td>".$user->login->username."</td>";
echo ""</tr>; }

* $feed = **$feed->getNextFeed();**
}

And what it does is that it shows all records of the feed exactly as
retrieveAllEntriesForFeed() instruction. But what I want to do is break them
into pages.

There's an atom:link element with a rel='next' that contains the link for the next step of results. Instead of $feed->getNextFeed(), you can instead call $feed->getNextLink()->getHref(), which will be the URL for the next step of results. You can see the format for the provisioning API-- it just uses the next username in the feed for paging.

Are there some examples for this task?

The closest examples are to retrieve 100 users starting at a particular username:

http://code.google.com/apis/apps/gdata_provisioning_api_v2.0_reference_php.html#Retrieve_100_Users_in_Domain_Example

Of course, you'll need to know the next username-- though you could always use the last username you saw and then just ignore the first result. However, I think the getNextLink method will work better.

Cheers,

-Ryan

Best regards.
Hugo

Ryan Boyd-3 wrote:
>
> When you echo out the previous and next URLs, what do you get? You won't
> be
> able to click on it and see it (because you wouldn't be sending the
> appropriate auth credentials), but you should be able to retrieve that
> feed.
>
> The following two blocks of code should be identical:
> ---
> while ($feed !== null) {
> foreach ($feed as $user) {
> echo "<tr>";
> echo "<td>".$user->login->username."</td>";
> echo ""</tr>; }
> * $feed = **$feed->getNextFeed();**
> }*----
> ---
> while ($feed !== null) {
> foreach ($feed as $user) {
> echo "<tr>";
> echo "<td>".$user->login->usern"</td>";
> echo ""</tr>; }
> * $feed = **$feed->getUserFeed($nextLink);*
> }----
>
> On Wed, Oct 21, 2009 at 4:34 PM, Hugo León <hugolec@...> wrote:
>
>>
>> Hello Ryan.
>>
>> For now I'm getting in the same manner the feed to the next page, but the
>> URL that I've got is
>>
>> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
>> and when I click it can't see the next page of the feed.
>>
>> What I do not want to do is show all the entries because we have one
>> GApps
>> domain with about 2,000 users, just as you recommended me.
>>
>> Here is the code:
>>
>> Zend_Loader::loadClass('Zend_Gdata');
>> Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
>> Zend_Loader::loadClass('Zend_Gdata_Gapps');
>> Zend_Loader::loadClass('Zend_Gdata_Feed');
>>
>> //ClientLogin
>> function getClientLoginHttpClient($user, $pass)
>> {
>> try{
>> $service = Zend_Gdata_Gapps::AUTH_SERVICE_NAME;
>> $client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass,
>> $service);
>> return $client;
>> } catch (Zend_Gdata_App_AuthException $e) {
>>
>> }
>> }
>>
>> $client = getClientLoginHttpClient($admin."@".$domain, $gappspass);
>> $gapps = new Zend_Gdata_Gapps($client, $domain);
>> $feed = $gapps->getUserFeed();
>> $previousLink = $feed->getLink("previous");
>> $nextLink = $feed->getLink("next");
>>
>> foreach ($feed as $user) {
>> echo "<tr>";
>> echo "<td>".$user->login->username."</td>";
>> echo ""</tr>;
>> }
>> if ($previousLink !== null) {
>> echo "previous url: " . $previousLink->href . " ";
>> $previousFeed = $gapps->getUserFeed($previousLink->href);
>> }
>> if ($nextLink !== null) {
>> echo "next url: " . $nextLink->href . " ";
>> $nextFeed = $gapps->getUserFeed($nextLink->href);
>> }
>>
>> Where should I put '$feedWithNextPageOfEntries = $feed->getNextFeed();' ?
>> or
>> how should I call it?.
>>
>> Thanks in advance.
>> Hugo
>>
>>
>> Ryan Boyd (Google) wrote:
>> >
>> > You probably have an existing $feed variable with the feed of results.
>> >
>> > Try:$feedWithNextPageOfEntries = $feed->getNextFeed();
>> > If you have a $service and an existing $feed and want to retrieve ALL
>> > entries (can be expensive), you can do:
>> > $feedWithAllEntries = $service->retrieveAllEntriesForFeed($feed);
>> >
>> > Cheers,
>> > -Ryan
>> >
>> > On Tue, Oct 13, 2009 at 2:56 PM, Hugo León <hugolec@...> wrote:
>> >
>> >>
>> >> Hello everyone.
>> >> I'm trying to get all users of a Google Apps domain and does it well.
>> >> But when there are domains with more than 100 users appear only the
>> first
>> >> 100, and with the function that comes into Zend website gives me the
>> link
>> >>
>> >>
>> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
>> >> ,
>> >> but obviously when I click on that link it does not work because I
>> need
>> >> authorization via ClientLogin again. And what I want to do is that it
>> >> only
>> >> shows me the next 100 users.
>> >>
>> >> How can I do this?
>> >> Thanks in advance.
>> >>
>> >> Hugo
>> >> --
>> >> View this message in context:
>> >>
>> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p25881614.html
>> >> Sent from the Zend gdata mailing list archive at Nabble.com.
>> >>
>> >>
>> >
>> >
>>
>> --
>> View this message in context:
>> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p26001897.html
>> Sent from the Zend gdata mailing list archive at Nabble.com.
>>
>>
>
>

--
View this message in context: http://old.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p26396478.html

Sent from the Zend gdata mailing list archive at Nabble.com.

Re: Working with Multi-page Feeds Google Provisioning API

2009-11-17T13:30:01Z

Hello again Ryan.

I decided to leave this issue until the end because it was difficult to perform. I have now reached the point where this is the only thing missing to complete the system.

I did what you suggested:

while ($feed !== null) {
foreach ($feed as $user) {
echo "<tr>";
echo "<td>".$user->login->username."</td>";
echo ""</tr>; }
* $feed = **$feed->getNextFeed();**
}

And what it does is that it shows all records of the feed exactly as retrieveAllEntriesForFeed() instruction. But what I want to do is break them into pages.

Are there some examples for this task?

Best regards.
Hugo

Ryan Boyd-3 wrote:

When you echo out the previous and next URLs, what do you get? You won't be
able to click on it and see it (because you wouldn't be sending the
appropriate auth credentials), but you should be able to retrieve that feed.

The following two blocks of code should be identical:
---
while ($feed !== null) {
foreach ($feed as $user) {
echo "<tr>";
echo "<td>".$user->login->username."</td>";
echo ""</tr>; }
* $feed = **$feed->getNextFeed();**
}*----
---
while ($feed !== null) {
foreach ($feed as $user) {
echo "<tr>";
echo "<td>".$user->login->usern"</td>";
echo ""</tr>; }
* $feed = **$feed->getUserFeed($nextLink);*
}----

On Wed, Oct 21, 2009 at 4:34 PM, Hugo León <hugolec@gmail.com> wrote:

>
> Hello Ryan.
>
> For now I'm getting in the same manner the feed to the next page, but the
> URL that I've got is
>
> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
> and when I click it can't see the next page of the feed.
>
> What I do not want to do is show all the entries because we have one GApps
> domain with about 2,000 users, just as you recommended me.
>
> Here is the code:
>
> Zend_Loader::loadClass('Zend_Gdata');
> Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
> Zend_Loader::loadClass('Zend_Gdata_Gapps');
> Zend_Loader::loadClass('Zend_Gdata_Feed');
>
> //ClientLogin
> function getClientLoginHttpClient($user, $pass)
> {
> try{
> $service = Zend_Gdata_Gapps::AUTH_SERVICE_NAME;
> $client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass,
> $service);
> return $client;
> } catch (Zend_Gdata_App_AuthException $e) {
>
> }
> }
>
> $client = getClientLoginHttpClient($admin."@".$domain, $gappspass);
> $gapps = new Zend_Gdata_Gapps($client, $domain);
> $feed = $gapps->getUserFeed();
> $previousLink = $feed->getLink("previous");
> $nextLink = $feed->getLink("next");
>
> foreach ($feed as $user) {
> echo "<tr>";
> echo "<td>".$user->login->username."</td>";
> echo ""</tr>;
> }
> if ($previousLink !== null) {
> echo "previous url: " . $previousLink->href . " ";
> $previousFeed = $gapps->getUserFeed($previousLink->href);
> }
> if ($nextLink !== null) {
> echo "next url: " . $nextLink->href . " ";
> $nextFeed = $gapps->getUserFeed($nextLink->href);
> }
>
> Where should I put '$feedWithNextPageOfEntries = $feed->getNextFeed();' ?
> or
> how should I call it?.
>
> Thanks in advance.
> Hugo
>
>
> Ryan Boyd (Google) wrote:
> >
> > You probably have an existing $feed variable with the feed of results.
> >
> > Try:$feedWithNextPageOfEntries = $feed->getNextFeed();
> > If you have a $service and an existing $feed and want to retrieve ALL
> > entries (can be expensive), you can do:
> > $feedWithAllEntries = $service->retrieveAllEntriesForFeed($feed);
> >
> > Cheers,
> > -Ryan
> >
> > On Tue, Oct 13, 2009 at 2:56 PM, Hugo León <hugolec@gmail.com> wrote:
> >
> >>
> >> Hello everyone.
> >> I'm trying to get all users of a Google Apps domain and does it well.
> >> But when there are domains with more than 100 users appear only the
> first
> >> 100, and with the function that comes into Zend website gives me the
> link
> >>
> >>
> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
> >> ,
> >> but obviously when I click on that link it does not work because I need
> >> authorization via ClientLogin again. And what I want to do is that it
> >> only
> >> shows me the next 100 users.
> >>
> >> How can I do this?
> >> Thanks in advance.
> >>
> >> Hugo
> >> --
> >> View this message in context:
> >>
> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p25881614.html
> >> Sent from the Zend gdata mailing list archive at Nabble.com.
> >>
> >>
> >
> >
>
> --
> View this message in context:
> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p26001897.html
> Sent from the Zend gdata mailing list archive at Nabble.com.
>
>

Two questions about Google Books Search API

2009-11-12T07:07:04Z

Hi,

I have two questions related to the use of Google Books Search API:

1) Does anyone know if it has a bug? When I do a search, I get incomplete data. The problem happens when I try to get the "publishers" data. For example: for a book from "Oxford University Press" I get "Oxford University Pr"... My code is as following:

$books = new Zend_Gdata_Books();
$query = $books->newVolumeQuery();
$term = $this->getRequest()->getParam('q');
$filter = "inauthor:{$term}";
$query->setMaxResults(6);
$query->setQuery($filter);
$feeds = $books->getVolumeFeed($query);
foreach ($feeds as $entry) {
$publishers = implode(" / ", $entry->getPublishers());
}

2) Is there a way to do a search in Google Books Search API by Google book ID?
I try to do the following, but I don't know if I will ever get a result:

$books = new Zend_Gdata_Books();
$query = $books->newVolumeQuery();
$id = "3uQQNAAACAAF";
$search = "http://www.google.com/books/feeds/volumes/{$id}";
$query->setQuery($search);
$feeds = $books->getVolumeFeed($query);

Thanks in advance,

Oriol

Re: Zend_Gdata_YouTube insertEntry check if the entry is uploaded

2009-11-10T08:56:41Z

Zend_Debug::dump($newEntry-> getVideoId ());

Is it right to manage error in the catch scope
like this 
catch (Zend_Gdata_App_HttpException $httpException) {
/* Manage Error */
echo $httpException->getRawResponseBody();
}
catch (Zend_Gdata_App_Exception $e) {
/* Manage Error */
echo $e->getMessage();
}

I also need to retrieve the video entry like in Browser-based upload
and I don't find the way :( 
Help me, please ;)
Bye.

whisher wrote:

Hi.
I should upload multiple flv files into youtube service 
in the script the moderator can decide if a video can be upload
if no movie with flag no_put
if yes a xhr request mark the video (to_put)
than with a cron
(the script retrieve video with flag to_put onsuccess flag put )
on error log_put and log the error
so I started with a snippet like this
<pre>
$yt = new Zend_Gdata_YouTube(getAuthSubHttpClient());
$myVideoEntry = new Zend_Gdata_YouTube_VideoEntry();

$filesource = $yt->newMediaFileSource('intro.flv');

$filesource->setContentType('video/x-flv');
$filesource->setSlug('intro.flv');

$myVideoEntry->setMediaSource($filesource);

$myVideoEntry->setVideoTitle('My Test Movie');
$myVideoEntry->setVideoDescription('My Test Movie');
// Note that category must be a valid YouTube category !
$myVideoEntry->setVideoCategory('Comedy');

// Set keywords, note that this must be a comma separated string
// and that each keyword cannot contain whitespace
$myVideoEntry->SetVideoTags('cars, funny');

// Optionally set some developer tags
$myVideoEntry->setVideoDeveloperTags(array('mydevelopertag',
'anotherdevelopertag'));

// Optionally set the video's location
$yt->registerPackage('Zend_Gdata_Geo');
$yt->registerPackage('Zend_Gdata_Geo_Extension');
$where = $yt->newGeoRssWhere();
$position = $yt->newGmlPos('37.0 -122.0');
$where->point = $yt->newGmlPoint($position);
$myVideoEntry->setWhere($where);

// Upload URI for the currently authenticated user
$uploadUrl =
'http://uploads.gdata.youtube.com/feeds/users/default/uploads';

// Try to upload the video, catching a Zend_Gdata_App_HttpException
// if availableor just a regular Zend_Gdata_App_Exception

try {
$newEntry = $yt->insertEntry($myVideoEntry,
$uploadUrl,
'Zend_Gdata_YouTube_VideoEntry');
echo "<pre>";
print_r($newEntry);
}

catch (Zend_Gdata_App_HttpException $httpException) {
echo $httpException->getRawResponseBody();
}
catch (Zend_Gdata_App_Exception $e) {
echo $e->getMessage();
}
put it in a loop with a checking on $newEntry
but I retrieve only NULL so

What's the way to check an upload ?

Is there a better way to set up the task ?

Thanks in advance
Bye

Thanks in advance

BA7-899 1.8.3 Warning: include(Zend\Gdata\Media\Extension\MediaFileSource.php)

2009-11-09T14:43:50Z

Hi.

I'm working on a project with zf 1.8.3 and I get the error in the subject (the script works with 1.9.*)

I should upload a file the code is quite the same

protected function _getFileSource(){
        $ext= ltrim(strtolower(strrchr($this->fileToUpload,'.')),'.');
        if($ext !== 'flv'){
           throw new Exception('Invalid extension'); 
        }
        $filesource = $this->yt->newMediaFileSource($this->fileToUpload);
        $filesource->setContentType('video/x-flv');
        $filesource->setSlug($this->fileToUpload);
        return $filesource;
    }
  
    protected function _uploadFile(){
        $myVideoEntry = new Zend_Gdata_YouTube_VideoEntry();
        /* ERROR */
        $myVideoEntry->setMediaSource($this->_getFileSource());
    }

Both Zend_Gdata_YouTube and Zend_Gdata_ClientLogin works
What's the 1.8.3 way ?

Thanks in advance.
Bye

Re: Zend_Gdata_YouTube insertEntry check if the entry is uploaded

2009-11-08T02:58:33Z

Is it right to manage error in the catch scope like this

catch (Zend_Gdata_App_HttpException $httpException) { /* Manage Error */ echo $httpException->getRawResponseBody(); } catch (Zend_Gdata_App_Exception $e) { /* Manage Error */ echo $e->getMessage(); }

I also need to retrieve the video entry like in Browser-based upload

and I don't find the way :(

Help me, please ;)

Bye.

whisher wrote:

Hi.

I should upload multiple flv files into youtube service

in the script the moderator can decide if a video can be upload

if no movie with flag no_put

if yes a xhr request mark the video (to_put)

than with a cron (the script retrieve video with flag to_put onsuccess flag put )

on error log_put and log the error

so I started with a snippet like this

$yt = new Zend_Gdata_YouTube(getAuthSubHttpClient());
$myVideoEntry = new Zend_Gdata_YouTube_VideoEntry();

$filesource = $yt->newMediaFileSource('intro.flv');

$filesource->setContentType('video/x-flv');
$filesource->setSlug('intro.flv');


$myVideoEntry->setMediaSource($filesource);

$myVideoEntry->setVideoTitle('My Test Movie');
$myVideoEntry->setVideoDescription('My Test Movie');
// Note that category must be a valid YouTube category !
$myVideoEntry->setVideoCategory('Comedy');

// Set keywords, note that this must be a comma separated string
// and that each keyword cannot contain whitespace
$myVideoEntry->SetVideoTags('cars, funny');

// Optionally set some developer tags
$myVideoEntry->setVideoDeveloperTags(array('mydevelopertag',
                                           'anotherdevelopertag'));

// Optionally set the video's location
$yt->registerPackage('Zend_Gdata_Geo');
$yt->registerPackage('Zend_Gdata_Geo_Extension');
$where = $yt->newGeoRssWhere();
$position = $yt->newGmlPos('37.0 -122.0');
$where->point = $yt->newGmlPoint($position);
$myVideoEntry->setWhere($where);

// Upload URI for the currently authenticated user
$uploadUrl =
    'http://uploads.gdata.youtube.com/feeds/users/default/uploads';

// Try to upload the video, catching a Zend_Gdata_App_HttpException
// if availableor just a regular Zend_Gdata_App_Exception

try {
    $newEntry = $yt->insertEntry($myVideoEntry,
                                 $uploadUrl,
                                 'Zend_Gdata_YouTube_VideoEntry');
   echo "";
   print_r($newEntry);
}
 
catch (Zend_Gdata_App_HttpException $httpException) {
    echo $httpException->getRawResponseBody();
} 
catch (Zend_Gdata_App_Exception $e) {
    echo $e->getMessage();
}
put it in a loop with a checking on $newEntry 
but I retrieve only NULL so


What's the way to check an upload ?

Is there a better way to set up the task ?

Thanks in advance
Bye


Thanks in advance

Zend_Gdata_YouTube insertEntry check if the entry is uploaded

2009-11-07T15:49:49Z

Hi.

I should upload multiple flv files into youtube service

in the script the moderator can decide if a video can be upload

if no movie with flag no_put

if yes a xhr request mark the video (to_put)

than with a cron (the script retrieve video with flag to_put onsuccess flag put )

on error log_put and log the error

so I started with a snippet like this

$yt = new Zend_Gdata_YouTube(getAuthSubHttpClient());
$myVideoEntry = new Zend_Gdata_YouTube_VideoEntry();

$filesource = $yt->newMediaFileSource('intro.flv');

$filesource->setContentType('video/x-flv');
$filesource->setSlug('intro.flv');


$myVideoEntry->setMediaSource($filesource);

$myVideoEntry->setVideoTitle('My Test Movie');
$myVideoEntry->setVideoDescription('My Test Movie');
// Note that category must be a valid YouTube category !
$myVideoEntry->setVideoCategory('Comedy');

// Set keywords, note that this must be a comma separated string
// and that each keyword cannot contain whitespace
$myVideoEntry->SetVideoTags('cars, funny');

// Optionally set some developer tags
$myVideoEntry->setVideoDeveloperTags(array('mydevelopertag',
                                           'anotherdevelopertag'));

// Optionally set the video's location
$yt->registerPackage('Zend_Gdata_Geo');
$yt->registerPackage('Zend_Gdata_Geo_Extension');
$where = $yt->newGeoRssWhere();
$position = $yt->newGmlPos('37.0 -122.0');
$where->point = $yt->newGmlPoint($position);
$myVideoEntry->setWhere($where);

// Upload URI for the currently authenticated user
$uploadUrl =
    'http://uploads.gdata.youtube.com/feeds/users/default/uploads';

// Try to upload the video, catching a Zend_Gdata_App_HttpException
// if availableor just a regular Zend_Gdata_App_Exception

try {
    $newEntry = $yt->insertEntry($myVideoEntry,
                                 $uploadUrl,
                                 'Zend_Gdata_YouTube_VideoEntry');
   echo "";
   print_r($newEntry);
}
 
catch (Zend_Gdata_App_HttpException $httpException) {
    echo $httpException->getRawResponseBody();
} 
catch (Zend_Gdata_App_Exception $e) {
    echo $e->getMessage();
}
put it in a loop with a checking on $newEntry 
but I retrieve only NULL so


What's the way to check an upload ?

Is there a better way to set up the task ?

Thanks in advance
Bye


Thanks in advance

Re: Working with Multi-page Feeds Google Provisioning API

2009-10-23T13:49:37Z

When you echo out the previous and next URLs, what do you get? You won't be able to click on it and see it (because you wouldn't be sending the appropriate auth credentials), but you should be able to retrieve that feed.

The following two blocks of code should be identical:

---

while ($feed !== null) {

foreach ($feed as $user) {
 echo "<tr>";
 echo "<td>".$user->login->username."</td>";
 echo ""</tr>;

}

$feed = $feed->getNextFeed();
}

----

---

while ($feed !== null) {

foreach ($feed as $user) {
 echo "<tr>";
 echo "<td>".$user->login->usern"</td>";
 echo ""</tr>;

}

$feed = $feed->getUserFeed($nextLink);
}

----

On Wed, Oct 21, 2009 at 4:34 PM, Hugo León <hugolec@...> wrote:

Hello Ryan.

For now I'm getting in the same manner the feed to the next page, but the
URL that I've got is

https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username

and when I click it can't see the next page of the feed.

What I do not want to do is show all the entries because we have one GApps
domain with about 2,000 users, just as you recommended me.

Here is the code:

Zend_Loader::loadClass('Zend_Gdata');
Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
Zend_Loader::loadClass('Zend_Gdata_Gapps');
Zend_Loader::loadClass('Zend_Gdata_Feed');

//ClientLogin
function getClientLoginHttpClient($user, $pass)
{
try{
$service = Zend_Gdata_Gapps::AUTH_SERVICE_NAME;
$client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass, $service);
return $client;
} catch (Zend_Gdata_App_AuthException $e) {

}
}

$client = getClientLoginHttpClient($admin."@".$domain, $gappspass);
$gapps = new Zend_Gdata_Gapps($client, $domain);
$feed = $gapps->getUserFeed();
$previousLink = $feed->getLink("previous");
$nextLink = $feed->getLink("next");

foreach ($feed as $user) {
echo "<tr>";
echo "<td>".$user->login->username."</td>";
echo ""</tr>;
}
if ($previousLink !== null) {
echo "previous url: " . $previousLink->href . " ";
$previousFeed = $gapps->getUserFeed($previousLink->href);
}
if ($nextLink !== null) {
echo "next url: " . $nextLink->href . " ";
$nextFeed = $gapps->getUserFeed($nextLink->href);
}

Where should I put '$feedWithNextPageOfEntries = $feed->getNextFeed();' ? or
how should I call it?.

Thanks in advance.
Hugo

Ryan Boyd (Google) wrote:
>
> You probably have an existing $feed variable with the feed of results.
>
> Try:$feedWithNextPageOfEntries = $feed->getNextFeed();
> If you have a $service and an existing $feed and want to retrieve ALL
> entries (can be expensive), you can do:
> $feedWithAllEntries = $service->retrieveAllEntriesForFeed($feed);
>
> Cheers,
> -Ryan
>
> On Tue, Oct 13, 2009 at 2:56 PM, Hugo León <hugolec@...> wrote:
>
>>
>> Hello everyone.
>> I'm trying to get all users of a Google Apps domain and does it well.
>> But when there are domains with more than 100 users appear only the first
>> 100, and with the function that comes into Zend website gives me the link
>>
>> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
>> ,
>> but obviously when I click on that link it does not work because I need
>> authorization via ClientLogin again. And what I want to do is that it
>> only
>> shows me the next 100 users.
>>
>> How can I do this?
>> Thanks in advance.
>>
>> Hugo
>> --
>> View this message in context:
>> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p25881614.html
>> Sent from the Zend gdata mailing list archive at Nabble.com.
>>
>>
>
>

--
View this message in context: http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p26001897.html

Sent from the Zend gdata mailing list archive at Nabble.com.

Re: Working with Multi-page Feeds Google Provisioning API

2009-10-21T16:34:43Z

Hello Ryan.

For now I'm getting in the same manner the feed to the next page, but the URL that I've got is https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username and when I click it can't see the next page of the feed.

What I do not want to do is show all the entries because we have one GApps domain with about 2,000 users, just as you recommended me.

Here is the code:

Zend_Loader::loadClass('Zend_Gdata');
Zend_Loader::loadClass('Zend_Gdata_ClientLogin');
Zend_Loader::loadClass('Zend_Gdata_Gapps');
Zend_Loader::loadClass('Zend_Gdata_Feed');

//ClientLogin
function getClientLoginHttpClient($user, $pass)
{
try{
$service = Zend_Gdata_Gapps::AUTH_SERVICE_NAME;
$client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass, $service);
return $client;
} catch (Zend_Gdata_App_AuthException $e) {

}
}

$client = getClientLoginHttpClient($admin."@".$domain, $gappspass);
$gapps = new Zend_Gdata_Gapps($client, $domain);
$feed = $gapps->getUserFeed();
$previousLink = $feed->getLink("previous");
$nextLink = $feed->getLink("next");

foreach ($feed as $user) {
echo "<tr>";
echo "<td>".$user->login->username."</td>";
echo ""</tr>;
}
if ($previousLink !== null) {
echo "previous url: " . $previousLink->href . " ";
$previousFeed = $gapps->getUserFeed($previousLink->href);
}
if ($nextLink !== null) {
echo "next url: " . $nextLink->href . " ";
$nextFeed = $gapps->getUserFeed($nextLink->href);
}

Where should I put '$feedWithNextPageOfEntries = $feed->getNextFeed();' ? or how should I call it?.

Thanks in advance.
Hugo

Ryan Boyd (Google) wrote:

You probably have an existing $feed variable with the feed of results.

Try:$feedWithNextPageOfEntries = $feed->getNextFeed();
If you have a $service and an existing $feed and want to retrieve ALL
entries (can be expensive), you can do:
$feedWithAllEntries = $service->retrieveAllEntriesForFeed($feed);

Cheers,
-Ryan

On Tue, Oct 13, 2009 at 2:56 PM, Hugo León <hugolec@gmail.com> wrote:

>
> Hello everyone.
> I'm trying to get all users of a Google Apps domain and does it well.
> But when there are domains with more than 100 users appear only the first
> 100, and with the function that comes into Zend website gives me the link
>
> https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username
> ,
> but obviously when I click on that link it does not work because I need
> authorization via ClientLogin again. And what I want to do is that it only
> shows me the next 100 users.
>
> How can I do this?
> Thanks in advance.
>
> Hugo
> --
> View this message in context:
> http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p25881614.html
> Sent from the Zend gdata mailing list archive at Nabble.com.
>
>

Re: Working with Multi-page Feeds Google Provisioning API

2009-10-14T16:39:10Z

You probably have an existing $feed variable with the feed of results.

Try:

$feedWithNextPageOfEntries = $feed->getNextFeed();

If you have a $service and an existing $feed and want to retrieve ALL entries (can be expensive), you can do:

$feedWithAllEntries = $service->retrieveAllEntriesForFeed($feed);

Cheers,

-Ryan

On Tue, Oct 13, 2009 at 2:56 PM, Hugo León <hugolec@...> wrote:

Hello everyone.
I'm trying to get all users of a Google Apps domain and does it well.
But when there are domains with more than 100 users appear only the first
100, and with the function that comes into Zend website gives me the link
https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username,
but obviously when I click on that link it does not work because I need
authorization via ClientLogin again. And what I want to do is that it only
shows me the next 100 users.

How can I do this?
Thanks in advance.

Hugo
--
View this message in context: http://www.nabble.com/Working-with-Multi-page-Feeds-Google-Provisioning-API-tp25881614p25881614.html
Sent from the Zend gdata mailing list archive at Nabble.com.

Working with Multi-page Feeds Google Provisioning API

2009-10-13T14:56:35Z

Hello everyone.
I'm trying to get all users of a Google Apps domain and does it well.
But when there are domains with more than 100 users appear only the first 100, and with the function that comes into Zend website gives me the link https://apps-apis.google.com/a/feeds/domain.com/user/2.0?startUsername=username, but obviously when I click on that link it does not work because I need authorization via ClientLogin again. And what I want to do is that it only shows me the next 100 users.

How can I do this?
Thanks in advance.

Hugo

Re: Calendar - retrieving just some properties

2009-10-08T13:43:20Z

On 10/8/2009 3:34 PM, Ryan Boyd wrote:

var_dump is also useful if you don't have all ZF classes available:
http://us2.php.net/manual/en/function.var-dump.php
On Thu, Oct 8, 2009 at 1:31 PM, Kyle Spraggs theman@... wrote:
On 10/8/2009 10:27 AM, Hector Virgen wrote:
You can use Zend_Debug::dump() to dump the contents of any variable to the screen.

Zend_Debug::dump($event->when);

--
Hector

On Wed, Oct 7, 2009 at 10:08 PM, emdeex <emdeex@...> wrote:

Hi, I've got my gdata-php app retrieving my calendar,

And I'm looking at http://framework.zend.com/manual/en/zend.gdata.calendar.html

I see from the example that I can echo properties like:

foreach ($eventFeed as $event) {
echo "<li>" . $event->title . " (Event ID: " . $event->id . ")</li>";
}

And the document says I can use "Additional properties such as ID,
author, when, event status, visibility, web content, and content,
among others ..."

I don't want title, or summary, or id, I just want the event date, or
better yet, the date and busy/free.

But $event->when returns "array" and I don't know what its
sub-properties are or how to access them.

Thanks for any help

GET is pretty common and the method I prefer to use.

-- Kyle Spraggs (SpiffyJr) http://www.spiffyjr.me

I accidentally replied to the wrong mail. var_dump and print_r are both useful for what you're trying to do.

-- 
Kyle Spraggs (SpiffyJr)
http://www.spiffyjr.me

Re: Calendar - retrieving just some properties

2009-10-08T13:34:13Z

var_dump is also useful if you don't have all ZF classes available:

http://us2.php.net/manual/en/function.var-dump.php

On Thu, Oct 8, 2009 at 1:31 PM, Kyle Spraggs <theman@...> wrote:

On 10/8/2009 10:27 AM, Hector Virgen wrote:
You can use Zend_Debug::dump() to dump the contents of any variable to the screen.

Zend_Debug::dump($event->when);

--
Hector

On Wed, Oct 7, 2009 at 10:08 PM, emdeex <emdeex@...> wrote:

Hi, I've got my gdata-php app retrieving my calendar,

And I'm looking at http://framework.zend.com/manual/en/zend.gdata.calendar.html

I see from the example that I can echo properties like:

foreach ($eventFeed as $event) {
echo "<li>" . $event->title . " (Event ID: " . $event->id . ")</li>";
}

And the document says I can use "Additional properties such as ID,
author, when, event status, visibility, web content, and content,
among others ..."

I don't want title, or summary, or id, I just want the event date, or
better yet, the date and busy/free.

But $event->when returns "array" and I don't know what its
sub-properties are or how to access them.

Thanks for any help

GET is pretty common and the method I prefer to use.

-- Kyle Spraggs (SpiffyJr) http://www.spiffyjr.me

Re: Calendar - retrieving just some properties

2009-10-08T13:31:25Z

On 10/8/2009 10:27 AM, Hector Virgen wrote:

You can use Zend_Debug::dump() to dump the contents of any variable to the screen.

Zend_Debug::dump($event->when);

--
Hector

On Wed, Oct 7, 2009 at 10:08 PM, emdeex <emdeex@...> wrote:

Hi, I've got my gdata-php app retrieving my calendar,

And I'm looking at http://framework.zend.com/manual/en/zend.gdata.calendar.html

I see from the example that I can echo properties like:

foreach ($eventFeed as $event) {
echo "<li>" . $event->title . " (Event ID: " . $event->id . ")</li>";
}

And the document says I can use "Additional properties such as ID,
author, when, event status, visibility, web content, and content,
among others ..."

I don't want title, or summary, or id, I just want the event date, or
better yet, the date and busy/free.

But $event->when returns "array" and I don't know what its
sub-properties are or how to access them.

Thanks for any help

GET is pretty common and the method I prefer to use.

-- 
Kyle Spraggs (SpiffyJr)
http://www.spiffyjr.me

Re: Calendar - retrieving just some properties

2009-10-08T08:27:06Z

You can use Zend_Debug::dump() to dump the contents of any variable to the screen.

Zend_Debug::dump($event->when);

--
Hector

On Wed, Oct 7, 2009 at 10:08 PM, emdeex <emdeex@...> wrote:

Hi, I've got my gdata-php app retrieving my calendar,

And I'm looking at http://framework.zend.com/manual/en/zend.gdata.calendar.html

I see from the example that I can echo properties like:

foreach ($eventFeed as $event) {
echo "<li>" . $event->title . " (Event ID: " . $event->id . ")</li>";
}

And the document says I can use "Additional properties such as ID,
author, when, event status, visibility, web content, and content,
among others ..."

I don't want title, or summary, or id, I just want the event date, or
better yet, the date and busy/free.

But $event->when returns "array" and I don't know what its
sub-properties are or how to access them.

Thanks for any help

Calendar - retrieving just some properties

2009-10-07T22:08:24Z

Hi, I've got my gdata-php app retrieving my calendar,

And I'm looking at http://framework.zend.com/manual/en/zend.gdata.calendar.html

I see from the example that I can echo properties like:

foreach ($eventFeed as $event) {
echo "<li>" . $event->title . " (Event ID: " . $event->id . ")</li>";
}

And the document says I can use "Additional properties such as ID,
author, when, event status, visibility, web content, and content,
among others ..."

I don't want title, or summary, or id, I just want the event date, or
better yet, the date and busy/free.

But $event->when returns "array" and I don't know what its
sub-properties are or how to access them.

Thanks for any help

Is it possible to use Gdata to retrieve contacts from Gmail

2009-08-26T08:23:22Z

I realize that there is no interface for Gmail among the ones made available by Gdata.

Does someone knows how to use it to retrieve an account contacts?

Thks

Marko

Correct way to retrieve events from non-default calendars?

2009-07-29T13:28:17Z

Hi folks,

So $calendar->getLink()->getHref(

) returns a full url like:

http://www.google.com/calendar/feeds/1bofflqv7fipee5cip4qmdgp40%40group.calendar.google.com

Plugging that into newEventQuery, e.g.:

$query = $service->newEventQuery('http://www.google.com/calendar/feeds/1bofflqv7fipee5cip4qmdgp40%40group.calendar.google.com');

creates a problem, because newEventQuery wants to include /default after it. $query->setUser(''); of course does not work, as any null user is set to "default" automatically.

I can of course strip "http://www.google.com/calendar/feeds/" out from the output of getHref() and feed that to setUser() but that seems a bit silly.

Is that how it's done, or is there something I'm missing?

-Josh

Correct way to retrieve events from non-default calendars?

2009-07-29T13:19:16Z

Hi folks,

So $calendar->getLink()->getHref() returns a full url like:

http://www.google.com/calendar/feeds/1bofflqv7fipee5cip4qmdgp40%40group.calendar.google.com

Plugging that into newEventQuery, e.g.:

$query = $service->newEventQuery('http://www.google.com/calendar/feeds/1bofflqv7fipee5cip4qmdgp40%40group.calendar.google.com');

creates a problem, because newEventQuery wants to include /default after it. $query->setUser(''); of course does not work, as any null user is set to "default" automatically.

I can of course strip "http://www.google.com/calendar/feeds/" out from the output of getHref() and feed that to setUser() but that seems a bit silly.

Is that how it's done, or is there something I'm missing?

-Josh

Correct way to retrieve events from non-default calendars?

2009-07-27T23:42:39Z

Re: Problem with Zend_Gdata_YouTube::getVideoFeed()

2009-07-22T11:14:58Z

Much appreciated Trevor, I'm going to roll back to 1.8.3 then until the
next release.

Trevor Johns wrote:

> 2009/7/22 Jeff Busby <jeff@...>:
>
>> Hi All,
>>
>> I was using ZF 1.8.0 and recently upgraded to 1.8.4 at which time I started getting the following error when querying Youtube:
>>
>> *Warning*: include(Zend/Gdata/Media/Extension/VideoQuery.php) [function.include <http://dev.yourmagz.local/media/index/article/function.include>]: failed to open stream: No such file or directory in */home/jbusby/workspace/library/Zend/Loader.php* on line *83
>>
>> *The results come back fine, but I'm unable to discover the problem here. I know the file Zend/Gdata/Media/Extension/VideoQuery.php does not exist, it's actually located in the Zend/Gdata/YouTube/ directory. I've search my entire project looking for where the missing file is being called but I've had no luck so far. The block of code that gives me the error is:
>>
>> $yt = new Zend_Gdata_YouTube();
>> $yt->setMajorProtocolVersion(2);
>> $query = $yt->newVideoQuery();
>> $query->setOrderBy('viewCount');
>> $query->setSafeSearch('strict');
>> $query->setFormat($this->_searchFormat);
>> $query->setVideoQuery($this->getTagwords());
>> $query->setMaxResults($this->getLimit());
>> $query->setStartIndex($this->getOffset());
>> $this->_results = $yt->getVideoFeed($query->getQueryUrl(2));
>>
>> Anyone else experienced this and hopefully has a solution?
>>
>> Cheers,
>>
>> Jeff Busby
>>
>
> Jeff,
> This looks like this issue:
>
> http://framework.zend.com/issues/browse/ZF-7013
>
> This will be fixed in the next release of Zend Framework. If you don't
> want to wait that long, you can either:
>
> 1. Download a development snapshot from here:
>
> http://framework.zend.com/code/browse/~tarball=zip/Zend_Framework/standard/trunk/trunk.zip
>
> 2. Use version 1.8.3:
>
> http://framework.zend.com/releases/ZendFramework-1.8.3/ZendFramework-1.8.3.tar.gz
>
> 3. Don't use Zend_Loader's autoloader functionality. (This bug only
> seems to show up if you're trying to autoload the classes.)
>
>

Problem with Zend_Gdata_YouTube::getVideoFeed()

2009-07-22T08:54:40Z

Hi All,

I was using ZF 1.8.0 and recently upgraded to 1.8.4 at which time I
started getting the following error when querying Youtube:

*Warning*: include(Zend/Gdata/Media/Extension/VideoQuery.php)
[function.include
<http://dev.yourmagz.local/media/index/article/function.include>]:
failed to open stream: No such file or directory in
*/home/jbusby/workspace/library/Zend/Loader.php* on line *83

*The results come back fine, but I'm unable to discover the problem
here. I know the file Zend/Gdata/Media/Extension/VideoQuery.php does
not exist, it's actually located in the Zend/Gdata/YouTube/
directory. I've search my entire project looking for where the missing
file is being called but I've had no luck so far.
The block of code that gives me the error is:

$yt = new Zend_Gdata_YouTube();
$yt->setMajorProtocolVersion(2);
$query = $yt->newVideoQuery();
$query->setOrderBy('viewCount');
$query->setSafeSearch('strict');
$query->setFormat($this->_searchFormat);
$query->setVideoQuery($this->getTagwords());
$query->setMaxResults($this->getLimit());
$query->setStartIndex($this->getOffset());
$this->_results = $yt->getVideoFeed($query->getQueryUrl(2));

Anyone else experienced this and hopefully has a solution?

Cheers,

Jeff Busby

Problems with Zend_Gdata_YouTube::getVideoFeed()

2009-07-22T08:52:16Z

Hi All,

I was using ZF 1.8.0 and recently upgraded to 1.8.4 at which time I
started getting the following error when querying Youtube:

*Warning*: include(Zend/Gdata/Media/Extension/VideoQuery.php)
[function.include
<http://dev.yourmagz.local/media/index/article/function.include>]:
failed to open stream: No such file or directory in
*/home/jbusby/workspace/library/Zend/Loader.php* on line *83

*The results come back fine, but I'm unable to discover the problem
here. I know the file Zend/Gdata/Media/Extension/VideoQuery.php does
not exist, it's actually located in the Zend/Gdata/YouTube/
directory. I've search my entire project looking for where the missing
file is being called but I've had no luck so far.

The block of code that gives me the error is:

$yt = new Zend_Gdata_YouTube();
$yt->setMajorProtocolVersion(2);
$query = $yt->newVideoQuery();
$query->setOrderBy('viewCount');
$query->setSafeSearch('strict');
$query->setFormat($this->_searchFormat);
$query->setVideoQuery($this->getTagwords());
$query->setMaxResults($this->getLimit());
$query->setStartIndex($this->getOffset());
$this->_results = $yt->getVideoFeed($query->getQueryUrl(2));

Anyone else experienced this and hopefully has a solution?

Cheers,

Jeff Busby

addGbaseAttribute('shipping') Error

2009-07-17T13:08:19Z

I am trying to set the shipping attribute for a google base item, but I am getting the following error no matter what I put for the value....

Text not allowed in this element. Please specify country, region, service, and price child elements instead.

Re: Trouble using Gdata Calendar

2009-07-08T18:13:46Z

Hi Trevor,

Thanks for the reply. I've posted in the comments for that issue. Please let me know if you need any more information.

Thanks.

Chee How

On Wed, Jul 8, 2009 at 6:02 AM, Trevor Johns <tjohns@...> wrote:

Chee, Leif,
This looks a lot like the issue that was reported here:

http://framework.zend.com/issues/browse/ZF-7013

However, so far I haven't been able to reproduce that issue on my end. If
you can come up with a reproducible test case, please feel free to attach
it to that issue so I can investigate further.

--
Trevor Johns

Original Message Follows:
------------------------
From: Chee How <chuacheehow@...>
Subject: [fw-gdata] Trouble using Gdata Calendar
Date: Tue, 7 Jul 2009 02:14:50 -0700 (PDT)

>
> To add to Leif's post
>
(http://www.nabble.com/Trouble-using-Gdata-Calendar-to23838933.html#a24191353),
> I also face a similar problem when using the Gapps API.
>
> When attempting to retrieve a user from the domain,
>
> $user = $gapps->retrieveUser('samwitwicky');
>
> I get the following errors:
>
> Warning: include(Zend/Gdata/Gapps/Extension/UserQuery.php)
> [function.include]: failed to open stream: No such file or directory in
> /home/cheeze/public_html/bayclips/library/Zend/Loader.php on line 83
>
> Warning: include() [function.include]: Failed opening
> 'Zend/Gdata/Gapps/Extension/UserQuery.php' for inclusion
>
(include_path='/home/cheeze/public_html/bayclips/application/../library:/home/cheeze/public_html/bayclips/library:.:/usr/share/php:/usr/share/pear')
> in /home/cheeze/public_html/bayclips/library/Zend/Loader.php on line 83
>
> Suspecting it is a 1.8.4 error, I switched the Gdata library from
version
> 1.7.8, and the code works with no warning. Is this a bug with 1.8.4?
> --
> View this message in context:
http://www.nabble.com/Trouble-using-Gdata-Calendar-tp24369673p24369673.html
> Sent from the Zend gdata mailing list archive at Nabble.com.
>
>

Trouble using Gdata Calendar

2009-07-07T02:14:50Z

To add to Leif's post (http://www.nabble.com/Trouble-using-Gdata-Calendar-to23838933.html#a24191353), I also face a similar problem when using the Gapps API.

When attempting to retrieve a user from the domain,

$user = $gapps->retrieveUser('samwitwicky');

I get the following errors:

Warning: include(Zend/Gdata/Gapps/Extension/UserQuery.php) [function.include]: failed to open stream: No such file or directory in /home/cheeze/public_html/bayclips/library/Zend/Loader.php on line 83

Warning: include() [function.include]: Failed opening 'Zend/Gdata/Gapps/Extension/UserQuery.php' for inclusion (include_path='/home/cheeze/public_html/bayclips/application/../library:/home/cheeze/public_html/bayclips/library:.:/usr/share/php:/usr/share/pear') in /home/cheeze/public_html/bayclips/library/Zend/Loader.php on line 83

Suspecting it is a 1.8.4 error, I switched the Gdata library from version 1.7.8, and the code works with no warning. Is this a bug with 1.8.4?

Re: Trouble using Gdata Calendar BA7-899

2009-06-24T12:36:53Z

Leif Hetlesæther skrev:

> Been using zf since 1.7.2 and recently tried the later 1.8.2. It throws
> an error using the following code:
>
>
> require_once 'Zend/Loader/Autoloader.php';
> $loader = Zend_Loader_Autoloader::getInstance();
> $service = Zend_Gdata_Calendar::AUTH_SERVICE_NAME;
> try
> {
> $client = Zend_Gdata_ClientLogin::getHttpClient($email,
> $pass, $service);
> }
> catch (Zend_Gdata_App_Exception $e)
> {
> echo "Error: Authentication with Google failed. Reason:
> BadAuthentication";
> exit;
> }
> $gdataCal = new Zend_Gdata_Calendar($client);
> $query = $gdataCal->newEventQuery();
>
> The code gives the following error:
>
> *Warning*:
> Zend_Loader::include(Zend/Gdata/Calendar/Extension/EventQuery.php)
> [function.Zend-Loader-include
> <http://lh.dev.nettkompetanse.no/diverse/function.Zend-Loader-include>]:
> failed to open stream: No such file or directory in
> */usr/share/php/ZendFramework-1.8.2/library/Zend/Loader.php* on line *83*
>
> *Warning*: Zend_Loader::include() [function.include
> <http://lh.dev.nettkompetanse.no/diverse/function.include>]: Failed
> opening 'Zend/Gdata/Calendar/Extension/EventQuery.php' for inclusion
> (include_path='.:/home/lh/libs:/usr/share/pear') in
> */usr/share/php/ZendFramework-1.8.2/library/Zend/Loader.php* on line *83
>
>
> *Am i doing something wrong or is this something for the bug tracker?
>

Tried 1.8.4 and the errors still persists. Everything seems to work
despite the errors thrown by the autoloader.

Currently just supressing the not found warnings.

$loader = Zend_Loader_Autoloader::getInstance();
$loader->suppressNotFoundWarnings(true);

Re: Trouble using Gdata Calendar

2009-06-24T12:33:29Z

Leif Hetlesæther skrev:

Gdata folders support

2009-06-20T01:21:30Z

Hi,

I poked around the Gdata library and haven't found an obvious reference to creating folders in GDocs:

http://code.google.com/apis/documents/docs/2.0/developers_guide_protocol.html#CreateFolders

What version of the GData API does the Zend library support?

If indeed there is no folder support, I'll write it up and send a patch, but could someone kindly let me know if I'm missing something before I head off to code it?

Cheers,

Matt

--------------------------------------

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myGengo http://mygengo.com

Efficient, quality translations that won't break the bank!

Gdata folders support

2009-06-20T01:19:13Z

Hi,

I poked around the Gdata library and haven't found an obvious reference to creating folders in GDocs:

http://code.google.com/apis/documents/docs/2.0/developers_guide_protocol.html#CreateFolders

What version of the GData API does the Zend library support?

If indeed there is no folder support, I'll write it up and send a patch, but could someone kindly let me know if I'm missing something before I head off to code it?

Cheers,

Matt

--------------------------------------

Need something translated?

myGengo http://mygengo.com

Efficient, quality translations that won't break the bank!

I'm ill, won't come, sorry

2009-06-18T09:40:24Z

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Out of Office Notice - Abwesenheitsnotiz

2009-06-18T02:54:46Z

Thank you for your message. I will be out of the office till June 22nd 2009. I will respond to your email as soon as possible on my return.

Thank you for your understanding.

Best regards,
Stefan Schmalhaus

--------------------------------

Vielen Dank für Ihre Nachricht. Ich bin bis zum 22. Juni 2009 nicht erreichbar. Ich werde auf Ihre E-Mail so schnell wie möglich nach meiner Rückkehr antworten.

Vielen Dank für Ihr Verständnis.

Mit freundlichen Grüßen
Stefan Schmalhaus

--
Dr. Stefan Schmalhaus
LOG2E - Web Design & Rich Internet Applications
Neuer Weg 89
D-47803 Krefeld

Email: info@...
Phone: +49 2151 761521
Fax: +49 2151 761524

Tests in our department

2009-06-18T02:53:39Z

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Obama's major declaration

2009-06-15T23:28:50Z

Epypavo

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