Nabble - codehaus - XStream

Re: Re: serialize a specific fields determined at runtime

2009-12-01T00:58:15Z

Hi ahmad,

ahmad wrote at Montag, 30. November 2009 00:42:

> Thanks Jörg for your reply
>
> i have configured XStream with the following, and still not getting the
> required behavior:
>
> public class FieldSelectors extends MapperWrapper {
>
> public FieldSelectors(Mapper wrapped) {
> super(wrapped);
> }
>
> @Override
> public boolean shouldSerializeMember(Class definedIn, String
> fieldName)
> {
>
> if (definedIn == Person.class & fieldName.equals("firstName")) {
> return true;
> } else {
> return super.shouldSerializeMember(definedIn, fieldName);
> }
>
> }
>
> }
>
> XStream xstream = new XStream() {
> protected MapperWrapper wrapMapper(MapperWrapper next) {
> return new FieldSelectors(next);
> }
>
> };
>
> FieldSelectors myMapper = (FieldSelectors) xstream.getMapper()
> .lookupMapperOfType(FieldSelectors.class);
> myMapper.shouldSerializeMember(Person.class, "firstName");
>
> Waiting your comments on this

My answer to the exactly same question is still exactly the same:

[snip]

>> This should work for serialization, but it does not work for
>> deserialization. The method is currently not called at deserialization
>> time if the member actually exists. This is actually an enhancement
>> request (XSTR-592). See my answer to your other mail for a solution at
>> deserialization time.

Read my answer to your question in thread "Serialize specific fields".

- Jörg

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