script question

I cooked up a simple script which runs only when gkrellm notes that my cpu
is getting too hot (because of summertime + setiathome is running 24/24).

To make sure the script runs only once at the same time and not twice
simultaneously I put in an ...if ... <compare the number of scripts
running> ... then ...

Now when the script runs (once only) and I issue separately the command:

ps aux |grep <scriptname> |grep -v grep |wc -l

this returns: 1

But when I run the script (with 'bash -x') that contains the same line "ps
aux.....wc -l" it always returns '2'.

I don't understand why. The number of processes running that include the
<scriptname> is always one in above example, so why does it return '2' if
the command is run inside the script and '1' when running separately?

Thanks to anyone who can explain.

Cheers,
=Dick Gevers=