split a beam element due to symmetry

[Haitham Mousad]

Hello group,
I'm doing an analysis which involves both 3D stress elements and ebam elements. To same computational efforts I'm using the symmetry to analyze only one half of the model. Unfortunately the beam element lies right on the center line and I defined it as a circular section (It is a steel rebar). I now need to make the ABAQUS take into consideration only half of this beam element.

I tried to define the section as a general section where defining I and A but an error massage appeared that the general section can't be used for this analysis.

I tried to use the partition cell option but it doesn't work with beam elements.

I tried to define the bad diameter so as to make the area of the new one half of the original one that had been used in the lab testing, I made some analysis and figured out that the inertial of the beam is influencing my analysis as even if I've the correct area in my last assumption. I'm for sure getting a wrong inertia.

Any suggestions?

Thanks a lot in advance

Regards,
Haitham M. Mousad


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[jeffergj]

try using the full section and assigning it a material with half the
stiffness.
You cant just reduce the area because the extensional stiffness is
proportional to area
and the bending ~~A**2


On Wed, Oct 21, 2009 at 1:20 PM, Haitham Mousad <hmousad85@...> wrote

>
>
> Hello group,
> I'm doing an analysis which involves both 3D stress elements and ebam
> elements. To same computational efforts I'm using the symmetry to analyze
> only one half of the model. Unfortunately the beam element lies right on the
> center line and I defined it as a circular section (It is a steel rebar). I
> now need to make the ABAQUS take into consideration only half of this beam
> element.
>
> I tried to define the section as a general section where defining I and A
> but an error massage appeared that the general section can't be used for
> this analysis.
>
> I tried to use the partition cell option but it doesn't work with beam
> elements.
>
> I tried to define the bad diameter so as to make the area of the new one
> half of the original one that had been used in the lab testing, I made some
> analysis and figured out that the inertial of the beam is influencing my
> analysis as even if I've the correct area in my last assumption. I'm for
> sure getting a wrong inertia.
>
> Any suggestions?
>
> Thanks a lot in advance
>
> Regards,
> Haitham M. Mousad
>
> __________________________________________________
> Do You Yahoo!?
> Tired of spam? Yahoo! Mail has the best spam protection around
> http://mail.yahoo.com
>
> [Non-text portions of this message have been removed]
>
>  
>

[Non-text portions of this message have been removed]